题意:一个数组arr,一个数字x,要使arr-x的最大子段最小,问该最小值. 三分x,复杂度logn,内层是最大子段的模板,只能用n复杂度的.因为是绝对值最大,正负各求一次,取大的.精度卡得不得了,要1e-12左右才能过.看着数据才调出精度的. 乱码: //#pragma comment(linker,"/STACK:1024000000,1024000000") #include<iostream> #include<cstdio> #include<s…

原题 题目定义了两个变量: poorness表示一个区间内和的绝对值. weakness表示一个所有区间最大的poornesss 题目要求你求一个x使得 a1 − x, a2 − x, ..., an − x这个序列的weakness最小 输出最小的weakness 显然,所求值是这样的一个函数 (因为是对abs取max,所以不可能出现有两个谷的不符合要求的函数) 所以我们可以三分,只有当x为ans时,我们才会得到最小值. 已知x时,如何求解最大子段和呢?,因为我们是取abs,所以在记录b[i]…

2017-08-27 17:24:07 writer:pprp 题意简述: • Codeforces 578C Weakness and poorness• 给定一个序列A• 一个区间的poorness定义为这个区间内和的绝对值• weakness等于所有区间最大的poorness• 求一个x使得,序列A全部减x后weakness最小• 1 ≤ n ≤ 2 * 1e5 这里用到了最大连续区间的和的知识点·,可以看上一篇博客 通过三分找最小值 AC代码如下: /* @theme:myprogram…

C. Weakness and Poorness Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/578/problem/C Description You are given a sequence of n integers a1, a2, ..., an. Determine a real number x such that the weakness of the sequence a1 -…

E. Weakness and Poorness time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a sequence of n integers a1, a2, ..., an. Determine a real number x such that the weakness of the seq…

E. Weakness and Poorness time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a sequence of n integers a1, a2, ..., an. Determine a real number x such that the weakness of the seq…

题目描述: E. Weakness and Poorness time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a sequence of n integers a1, a2, ..., *a**n*. Determine a real number x such that the weakness…

Raising Bacteria 题意:盒子里面的细菌每天会数量翻倍,你可以在任意一天放任意多的细菌,最后要使得某天盒子里面的细菌数量等于x,求至少要放多少个细菌 思路:显然,翻倍即为二进制左移一位,那么放入一个细菌,到第二天就变成2个二进制下即为1->10对于任意二进制数 如:1001110,只需要在第一天放1个,第4.5.6天各放一个,再等一天,就可以了.所以答案显然是x在二进制下1的个数. Finding Team Member 题意:2n个人,每两个人组合的队伍有aij的力量.每个人都希…

显然f(x)是个凹函数,三分即可,计算方案的时候dp一下.eps取大了会挂精度,指定循环次数才是正解. #include<bits/stdc++.h> using namespace std; ; ; double a[maxn]; double d1[maxn],d2[maxn]; int n; inline double cal(double x) { ., a2 = .; ; i <= n; i++){ d1[i] = max(.,d1[i-])+a[i]-x; a1 = max(…

You are given a sequence of n integers a1, a2, ..., an. Determine a real number x such that the weakness of the sequence a1 - x, a2 - x, ..., an - x is as small as possible. The weakness of a sequence is defined as the maximum value of the poorness o…