1141 PAT Ranking of Institutions
题意:给出考生id(分为乙级、甲级和顶级),取得的分数和所属学校。计算各个学校的所有考生的带权总成绩,以及各个学校的考生人数。最后对学校进行排名。
思路:本题的研究对象是学校,而不是考生!因此,建立学校的结构体Record,记录学校的校名,考生人数,排名,成绩等信息。利用map<校名,该学校对应的结构体>构造映射,然后在读入数据的时候就可以更新该学校的分数,学生人数。数据读入完毕后,根据计算规则求出各个学校的带权总成绩,再把结构体放到vector中排序一下,确定排名,就好了。
代码:
#include <cstdio>
#include <cctype>
#include <string>
#include <vector>
#include <map>
#include <iostream>
#include <algorithm>
#include <fstream>
using namespace std;
struct Record{
int rank;
string sch;
int ScoreB,ScoreA,ScoreT,tws;
int cnt;
Record():rank(),sch(),ScoreA(),ScoreT(),tws(),cnt(){}
};
map<string,Record> mp;
vector<Record> vec;
bool cmp(Record a,Record b)
{
if(a.tws!=b.tws) return a.tws>b.tws;
else if(a.cnt!=b.cnt) return a.cnt<b.cnt;
else return a.sch<b.sch;
}
int main()
{
//ifstream cin("pat.txt");
int n;
cin>>n;
string sch,id;
int score;
;i<n;i++){
cin>>id>>score>>sch;
;i<sch.size();i++)
sch[i]=tolower(sch[i]);
mp[sch].cnt++;
mp[sch].sch=sch;
]=='B') mp[sch].ScoreB+=score;
]=='A') mp[sch].ScoreA+=score;
else mp[sch].ScoreT+=score;
}
for(auto it:mp){
Record rec=it.second;
rec.tws=rec.ScoreB/1.5 + rec.ScoreA + rec.ScoreT*1.5;
vec.push_back(rec);
}
sort(vec.begin(),vec.end(),cmp);
;i<vec.size();i++){
) vec[i].rank=;
].tws) vec[i].rank=vec[i-].rank;
;
}
cout<<vec.size()<<'\n';
for(auto it:vec)
cout<<it.rank<<' '<<it.sch<<' '<<it.tws<<' '<<it.cnt<<'\n';
;
}
1141 PAT Ranking of Institutions的更多相关文章
- 1141 PAT Ranking of Institutions[难]
1141 PAT Ranking of Institutions (25 分) After each PAT, the PAT Center will announce the ranking of ...
- PAT 甲级 1141 PAT Ranking of Institutions
https://pintia.cn/problem-sets/994805342720868352/problems/994805344222429184 After each PAT, the PA ...
- [PAT] 1141 PAT Ranking of Institutions(25 分)
After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...
- 1141 PAT Ranking of Institutions (25 分)
After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...
- PAT 1141 PAT Ranking of Institutions
After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...
- PAT_A1141#PAT Ranking of Institutions
Source: PAT A1141 PAT Ranking of Institutions (25 分) Description: After each PAT, the PAT Center wil ...
- A1141. PAT Ranking of Institutions
After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...
- PAT A1141 PAT Ranking of Institutions (25 分)——排序,结构体初始化
After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...
- PAT Ranking (排名)
PAT Ranking (排名) Programming Ability Test (PAT) is organized by the College of Computer Science and ...
随机推荐
- pandas 选取数据 修改数据 loc iloc []
pandas选取数据可以通过 loc iloc [] 来选取 使用loc选取某几列: user_fans_df = sample_data.loc[:,['uid','fans_count']] 使 ...
- 【转】Java设计模式-单例模式详解
原创作品,可以转载,但是请标注出处地址:http://www.cnblogs.com/V1haoge/p/6510196.html 所谓单例,指的就是单实例,有且仅有一个类实例,这个单例不应该由人来控 ...
- colorlog的三个例子
例1:默认的log_colors import logging from logging.handlers import RotatingFileHandler from colorlog impor ...
- JSON字符串与JSON对象的互相转换
比如工作中遇到的app强制退出功能的参数问题 首先定义一个JSON字符串 objectStr : String value=UUID.randomUUID().toString();SimpleDat ...
- Pro C/C++ 编程中值得注意的问题
1.宿主字符串存储Oracle自动补零问题. EXEC SQL BEGIN DECLARE SECTION; unsigned char liId[25]; EXEC SQL END DECLARE ...
- Updated: Database Partitioning with EBS Whitepaper
Partitioning allows a single database table and its associated indexes to be broken into smaller com ...
- 012——VUE中todos示例讲解class中应用表达式
<!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title> ...
- nivicat premium连接阿里云数据库
1.首先打开Navicat,文件>新建连接>MySQL连接,其他的如一图所示 其中: 连接名:自己取一个名字 主机名:填写mysql的地址 用户名:mysql的登录的用户名 密码:登录的密 ...
- 你真的对java static了解吗,代码优化可能更加简单
static修饰的成员变量和成员方法独立于该类的任何对象.也就是说,它不依赖类特定的实例,被类的所有实例共享. 只要这个类被加载,Java虚拟机就能根据类名在运行时数据区的方法区内定找到他们.因此,s ...
- C++ Primer 第四版中文版
C++Primer是C++的经典教程. 开始时间:2014-08-10 完成时间:2014-08-28 学习成果:基础语法+