A. The Fair Nut and the Best Path 题意:给定有点权,有边权的树,让你选择一条链(也可以是只有一个点),使得点权之和-边权最大. 思路:裸的树形DP,我们用dp[i]表示i的子树里某个点到i这条链的最大值,然后用次大值更新答案即可. 具体的,每个dp[i]初始化=a[i]; 对于i连出去的边-> (i,j),用它来更新答案,max(ans,dp[i]+dp[j]-len[i,j]):然后用它更新dp[i],max(dp[i],dp[i]-len[i,j]): 因
题目链接: DZY Loves Partition Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 323 Accepted Submission(s): 127 Problem Description DZY loves partitioning numbers. He wants to know whether it is
java.lang.IllegalStateException: Web app root system property already set to different value: 'webapp.root' = [....\tmp1\wtpwebapps\workreport\] instead of [.....\wtpwebapps\ApprovalFront\] - Choose unique values for the 'webAppRootKey' context-param
1027 Colors in Mars (20 分) People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and th