UVA 10066 The Twin Towers(LCS)
Problem B
The Twin Towers
Input: standard input
Output: standard output
Once upon a time, in an ancient Empire, there were two towers of dissimilar shapes in two different cities. The towers were built by putting circular tiles one upon another. Each of the tiles was of the same height and had integral radius. It is no wonder that though the two towers were of dissimilar shape, they had many tiles in common.
However, more than thousand years after they were built, the Emperor ordered his architects to remove some of the tiles from the two towers so that they have exactly the same shape and size, and at the same time remain as high as possible. The order of the tiles in the new towers must remain the same as they were in the original towers. The Emperor thought that, in this way the two towers might be able to stand as the symbol of harmony and equality between the two cities. He decided to name them the Twin Towers.
Now, about two thousand years later, you are challenged with an even simpler problem: given the descriptions of two dissimilar towers you are asked only to find out the number of tiles in the highest twin towers that can be built from them.
Input
The input file consists of several data blocks. Each data block describes a pair of towers.
The first line of a data block contains two integers N1 and N2 (1 <= N1, N2 <= 100) indicating the number of tiles respectively in the two towers. The next line contains N1 positive integers giving the radii of the tiles (from top to bottom) in the first tower. Then follows another line containing N2 integers giving the radii of the tiles (from top to bottom) in the second tower.
The input file terminates with two zeros for N1 and N2.
Output
For each pair of towers in the input first output the twin tower number followed by the number of tiles (in one tower) in the highest possible twin towers that can be built from them. Print a blank line after the output of each data set.
Sample Input
7 6
20 15 10 15 25 20 15
15 25 10 20 15 20
8 9
10 20 20 10 20 10 20 10
20 10 20 10 10 20 10 10 20
0 0
Sample Output
Twin Towers #1
Number of Tiles : 4
Twin Towers #2
Number of Tiles : 6
题目大意:给定构成两座塔瓦片,从中挑选出一些瓦片留下,使得两座塔有相同的高度和结构,成为具有最多数量瓦片的双胞胎塔。
动态规划LCS
# include<cstdio>
# include<cstring>
# include<iostream>
using namespace std;
int N1,N2;
int s1[],s2[];
int dp[][];
int main()
{
int cas=;
int i,j;
while(scanf("%d%d",&N1,&N2)&&N1&&N2)
{
for(i=; i<=N1; i++)
scanf("%d",&s1[i]);
for(i=; i<=N2; i++)
scanf("%d",&s2[i]);
printf("Twin Towers #%d\n",cas++); memset(dp,,sizeof(dp)); //边界条件
int ans=;
for(i=; i<=N1; i++) //状态转移
for(j=; j<=N2; j++)
{
if(s1[i]==s2[j])
dp[i][j] = dp[i-][j-]+;
else
dp[i][j] = max(dp[i-][j],dp[i][j-]);
if(ans<dp[i][j])
ans = dp[i][j];
}
printf("Number of Tiles : %d\n\n",ans);
}
return ;
}
UVA 10066 The Twin Towers(LCS)的更多相关文章
- UVA.10066 The Twin Towers (DP LCS)
UVA.10066 The Twin Towers (DP LCS) 题意分析 有2座塔,分别由不同长度的石块组成.现在要求移走一些石块,使得这2座塔的高度相同,求高度最大是多少. 问题的实质可以转化 ...
- uva 10066 The Twin Towers (最长公共子)
uva 10066 The Twin Towers 标题效果:最长公共子. 解题思路:最长公共子. #include<stdio.h> #include<string.h> # ...
- UVa 10192 - Vacation & UVa 10066 The Twin Towers ( LCS 最长公共子串)
链接:UVa 10192 题意:给定两个字符串.求最长公共子串的长度 思路:这个是最长公共子串的直接应用 #include<stdio.h> #include<string.h> ...
- LightOJ1126 Building Twin Towers(DP)
题目 Source http://www.lightoj.com/volume_showproblem.php?problem=1126 Description Professor Sofdor Al ...
- UVA 10066 The Twin Towers
裸最长公共子序列 #include<time.h> #include <cstdio> #include <iostream> #include<algori ...
- 【实习记】2014-08-29算法学习Boyer-Moore和最长公共子串(LCS)
昨天的问题方案一:寻找hash函数,可行性极低.方案二:载入内存,维护成一个守护进程的服务.难度比较大.方案三:使用前5位来索引,由前3位增至前5位唯一性,理论上是分拆记录扩大100倍,但可以 ...
- 动态规划法(十)最长公共子序列(LCS)问题
问题介绍 给定一个序列\(X=<x_1,x_2,....,x_m>\),另一个序列\(Z=<z_1,z_2,....,z_k>\)满足如下条件时称为X的子序列:存在一个严格 ...
- uva 1153 顾客是上帝(贪心)
uva 1153 顾客是上帝(贪心) 有n个工作,已知每个工作需要的时间q[i]和截止时间d[i](必须在此前完成),最多能完成多少个工作?工作只能串行完成,第一项任务开始的时间不早于时刻0. 这道题 ...
- 最长公共子序列(LCS)、最长递增子序列(LIS)、最长递增公共子序列(LICS)
最长公共子序列(LCS) [问题] 求两字符序列的最长公共字符子序列 问题描述:字符序列的子序列是指从给定字符序列中随意地(不一定连续)去掉若干个字符(可能一个也不去掉)后所形成的字符序列.令给定的字 ...
随机推荐
- HW4.7
public class Solution { public static void main(String[] args) { double rate = 0.05; double balance ...
- Java读取文件夹大小的6种方法及代码
(一)单线程递归方式 package com.taobao.test; import java.io.File; public class TotalFileSizeSequential { publ ...
- CSS3 keyframes动画实现弹跳效果
首先,“回到顶部”.“用户反馈”这两个按钮是通过定位放在左下角上. (1)“回到顶部”的按钮只有当滚动条有出现下滑时才出现 (2)“用户反馈”按钮,用户刚打开时会抖动一下,引起用户的注意,然后才定住. ...
- DAS 原文出自【比特网】
http://www.360doc.com/content/13/1114/11/10504424_329109113.shtml
- Palindrome(poj3974)(manacher算法)
http://poj.org/problem?id=3974 Palindrome Time Limit: 15000MSMemory Limit: 65536K Total Submissions: ...
- CameraTest
from com.android.monkeyrunner import MonkeyRunner,MonkeyDevice,MonkeyImage #device = MonkeyRunner.wa ...
- 多态VI的创建
比较适合使用多态VI的场合:一个算法会应用到几种不同的数据类型上.比如读写 INI 文件的 VI,它 们既可以读写数值型的数据,也可以读写字符串.布尔等数据类型. 实现多态 VI 之前,一般先实现它的 ...
- 【转】cocos2d-x 模仿计时器效果,动态增加分数——2013-08-25 16
http://www.cocos2dev.com/?p=90 游戏中要用到分数是动态增加的,而不是瞬间加上去的. bool HelloWorld::init() { if ( !CCLayer::in ...
- oracle修改字段类型
有一个表名为tb,字段段名为name,数据类型nchar(20). 1.假设字段数据为空,则不管改为什么字段类型,可以直接执行:alter table tb modify (name nvarchar ...
- 一种通用数据采集的schema定义形式
{ "name": "凤凰金融", "notice": { "data": "attribute", ...