It is probably because Willow was the last link to her parents and a pastime that goes back to her own childhood. It really does feel like the end of an era.

这很可能是因为Willow是她与父母最后的联系,也是一种对自己童年娱乐消遣的追溯。这真的感觉像是一个时代的终结。

probably 英 ['prɒbəblɪ] 美 ['prɑbəbli]

adv. 大概;或许;很可能

Willow 人名;(英)威洛,薇洛(女名)

own 英 [əʊn] 美 [on]

vt. 拥有;承认
vi. 承认
adj. 自己的;特有的
n. 自己的
n. (Own)人名;(阿拉伯)奥恩

childhood  ['tʃaɪldhʊd]  n. 童年时期;幼年时代

era  英 ['ɪərə] 美 ['ɪrə]                                    # period  n. 周期,期间;时期;月经;课时;(语法学)句点,句号  adj. 某一时代的

n. 时代;年代;纪元
n. (Era)人名;(意、芬、印)埃拉

every day a practice —— morning(7)的更多相关文章

  1. ConCurrent in Practice小记 (3)

    ConCurrent in Practice小记 (3) 高级同步技巧 Semaphore Semaphore信号量,据说是Dijkstra大神发明的.内部维护一个许可集(Permits Set),用 ...

  2. ConCurrent in Practice小记 (2)

    Java-ConCurrent2.html :first-child{margin-top:0!important}img.plugin{box-shadow:0 1px 3px rgba(0,0,0 ...

  3. ConCurrent in Practice小记 (1)

    ConCurrent in Practice小记 (1) 杂记,随书自己写的笔记: 综述问题 1.线程允许在同一个进程中的资源,包括共享内存,内存句柄,文件句柄.但是每个进程有自己的程序计数器,栈和局 ...

  4. ConCurrent in Practice小记 (4)

    ConCurrent in Practice小记 (4) Executors Callable && Future <T> Callable:此接口有一个call()方法. ...

  5. every day a practice —— morning(6)

    "Nearly one in five job ads for China's 2018 national civil service called for 'men only' or 'm ...

  6. every day a practice —— morning(5)

    Huawei has not been accused of wrongdoing. As an administrative subpoena, the Treasury document does ...

  7. every day a practice —— morning(3)

    "WeChat does not store any chat histories. They are stored only on users' phones, computers or ...

  8. every day a practice —— morning(2)

    Two years at sea have fostered a close relationship between the two fellow sailors as they cross the ...

  9. every day a practice —— morning(4)

    If there’s one thing New Yorkers love more than discovering a new secret remedy, it’s telling other ...

随机推荐

  1. Codeforces Round #479 (Div. 3)题解

    CF首次推出div3给我这种辣鸡做,当然得写份博客纪念下 A. Wrong Subtraction time limit per test 1 second memory limit per test ...

  2. topcoder srm 694 div1 -3

    1.给出$n$个数字,将其分成三个非空的组,每组的权值为该组所有数字的抑或.选择一种分法使得三组的权值和最大? 思路:记录前两组的权值且三组有没有数字时第三组的值.(当前两组的值知道时第三组的权值是确 ...

  3. Docker 使用Docker-Compose编排容器

    简介: Docker Compose是一个用来定义和运行复杂应用的Docker工具.一个使用Docker容器的应用,通常由多个容器组成.使用Docker Compose不再需要使用shell脚本来启动 ...

  4. Oracle面试相关

    存储过程: https://www.cnblogs.com/taiguyiba/p/7809310.html https://www.cnblogs.com/lideng/p/3427822.html ...

  5. call继承父级属性,prototype继承父级方法

    <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...

  6. 4-Three-Matterhorn man

    What was the main objective of early mountain climbers?   ①Modern alpinists try to climb mountains b ...

  7. 【ASP.NET】The CodeDom provider type “Microsoft.CodeDom.Providers.DotNetCompilerPlatform.CSharpCodeProvider” could not be located

    一般是asp.net的项目在启动的时候会报这个错误. 页面显示成: 我推测的原因是由于project的build的输出属性改了, 非bin目录下, 导致这个问题. 解决这个问题的方案有两个: 1. 改 ...

  8. docker 命令2

    docker build -t dvm.adsplatformproxy:v1.0.0 . #build images docker run -e WWNamespace=dev -e ZKServe ...

  9. 【转载】EclEmma工具介绍

    https://wenku.baidu.com/view/1017567e5acfa1c7aa00cc5f.html https://www.ibm.com/developerworks/cn/rat ...

  10. 让你的 Python 代码优雅又地道

    示例代码和引用的语录都来自Raymond的演讲.这是我按我的理解整理出来的,希望你们理解起来跟我一样顺畅! 遍历一个范围内的数字 for i in [0, 1, 2, 3, 4, 5]: print  ...