【Django】Django 如何支持 分组查询、统计？

代码：

from django.db.models import Sum
        alarm_sum_group_items = models.FILE_PROTECT_ALARM.objects.filter(customer_id=customer_id).values('device_hash').annotate(alarm_sum=Sum('cmn_merge_count'))
        data = []
        for item in alarm_sum_group_items:
            tmp = {}
            tmp['customer_id'] = customer_id
            tmp['device_hash'] = item['device_hash']
            tmp['alarm_sum'] = item['alarm_sum']
            data.append(tmp)
        return APIResponse(status=status_code.success, data=data)

参考资料：

https://www.douban.com/group/topic/18930354/?type=like

http://www.tuicool.com/articles/aiUBVrn

https://www.douban.com/group/topic/18930354/?type=like

http://stackoverflow.com/questions/19101665/django-how-to-do-select-count-group-by-and-order-by

https://my.oschina.net/duoduo3369/blog/199190

http://stackoverflow.com/questions/327807/django-equivalent-for-count-and-group-by

https://segmentfault.com/q/1010000005828240

http://www.cnblogs.com/BeginMan/archive/2013/05/27/3101322.html

http://blog.csdn.net/iloveyin/article/details/46380619

http://www.jb51.net/article/69774.htm