B. Gleb And Pizza

time limit per test:2 seconds
memory limit per test:256 megabytes
input:standard input
output:standard output

Gleb ordered pizza home. When the courier delivered the pizza, he was very upset, because several pieces of sausage lay on the crust, and he does not really like the crust.

The pizza is a circle of radius r and center at the origin. Pizza consists of the main part — circle of radius r - d with center at the origin, and crust around the main part of the width d. Pieces of sausage are also circles. The radius of the i -th piece of the sausage is ri, and the center is given as a pair (xi, yi).

Gleb asks you to help determine the number of pieces of sausage caught on the crust. A piece of sausage got on the crust, if it completely lies on the crust.

Input

First string contains two integer numbers r and d (0 ≤ d < r ≤ 500) — the radius of pizza and the width of crust.

Next line contains one integer number n — the number of pieces of sausage (1 ≤ n ≤ 105).

Each of next n lines contains three integer numbers xi, yi and ri ( - 500 ≤ xi, yi ≤ 500, 0 ≤ ri ≤ 500), where xi and yi are coordinates of the center of i-th peace of sausage, ri — radius of i-th peace of sausage.

Output

Output the number of pieces of sausage that lay on the crust.

Examples
Input
8 4
7
7 8 1
-7 3 2
0 2 1
0 -2 2
-3 -3 1
0 6 2
5 3 1
Output
2
Input
10 8
4
0 0 9
0 0 10
1 0 1
1 0 2
Output
0
Note

Below is a picture explaining the first example. Circles of green color denote pieces of sausage lying on the crust.

题目链接:http://codeforces.com/contest/842/problem/B

分析:根据圆心到原点的距离这个东西判断一下圆在不在那个环里面就好

下面给出(Python 3.5.2)AC代码:

 r,d=map(int,input().split())
n=int(input())
k=0
for i in range(n):
x,y,w=map(int,input().split())
l=(x**2+y**2)**(1/2)
if l-w>=r-d and l+w<=r:
k+=1
print(k)

Codeforces 842B Gleb And Pizza【几何,水】的更多相关文章

  1. Gleb And Pizza CodeForces - 842B

    CodeForces - 842B #include<bits/stdc++.h> using namespace std; int main() { int r,d,t; double ...

  2. Codeforces Round #430 B. Gleb And Pizza

    Gleb ordered pizza home. When the courier delivered the pizza, he was very upset, because several pi ...

  3. 【Codeforces Round #430 (Div. 2) B】Gleb And Pizza

    [链接]点击打开链接 [题意] 在这里写题意 [题解] 根据圆心到原点的距离这个东西判断一下圆在不在那个环里面就好 [错的次数] 0 [反思] 在这了写反思 [代码] #include <cst ...

  4. Educational Codeforces Round 7 B. The Time 水题

    B. The Time 题目连接: http://www.codeforces.com/contest/622/problem/B Description You are given the curr ...

  5. Educational Codeforces Round 7 A. Infinite Sequence 水题

    A. Infinite Sequence 题目连接: http://www.codeforces.com/contest/622/problem/A Description Consider the ...

  6. Codeforces Testing Round #12 A. Divisibility 水题

    A. Divisibility Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/597/probl ...

  7. Codeforces Beta Round #37 A. Towers 水题

    A. Towers 题目连接: http://www.codeforces.com/contest/37/problem/A Description Little Vasya has received ...

  8. codeforces 712B B. Memory and Trident(水题)

    题目链接: B. Memory and Trident time limit per test 2 seconds memory limit per test 256 megabytes input ...

  9. codeforces 712A A. Memory and Crow(水题)

    题目链接: A. Memory and Crow time limit per test 2 seconds memory limit per test 256 megabytes input sta ...

随机推荐

  1. Chef 自动化运维:开始“烹饪”

    在 Chef Workstation 上创建了一个 cookbook 之后,我们执行以下命令来进行测试: chef-client --local-mode --override-runlist fir ...

  2. <大话设计模式>笔记

    读完了<大话设计模式>这本书,收获很多,对程序设计有了很多新的理解.将每章模式的大概要点做了些笔记以备查阅,一些设计模式书读完也对其了解得不是很透彻,需要以后在实践中来不断地加深理解吧.读 ...

  3. Hibernate学习---单表查询

    我们都知道SQL是非常强大的,为什么这么说呢?相信学过数据库原理的同学们都深有体会,SQL语句变化无穷,好毫不夸张的说可以实现任意符合我们需要的数据库操作,既然前面讲到Hibernate非常强大,所以 ...

  4. [数据结构]C语言队列的实现

    我个人把链表.队列.栈分为一类,然后图.树分为一类.(串不考虑),分类的理由就是每一类有规律可循,即你能通过修改极少数的代码把链表变成队列.栈.(这里我们不考虑其他诸如设计模式等因素),因此本贴在讲完 ...

  5. 如何给动态添加的form表单控件添加表单验证

    最近使用jQuery Validate做表单验证很方便,api地址为http://www.runoob.com/jquery/jquery-plugin-validate.html 但是在使用的时候也 ...

  6. STM32基础分析——USART的DMA模式

    有关USART的DMA传输模式,其基本的概念和配置,网上有很多博客和教程都有,这里不再赘述,只是记录一下比较容易忽视而造成调试不通的问题. 1. 串口发送和接收分属两个DMA通道 一般方式操作串口时, ...

  7. SpringMVC底层数据传输校验的方案(修改版)

    团队的项目正常运行了很久,但近期偶尔会出现BUG.目前观察到的有两种场景:一是大批量提交业务请求,二是生成批量导出文件.出错后,再执行一次就又正常了. 经过跟踪日志,发现是在Server之间进行jso ...

  8. php-fpm开机启动

    php-fpm开机自动启动脚本 网上有各种版本的php-fpm开机自动启动脚本, 其实你编译后源目录已经生成自动脚本.不用做任何修改即用. cp {php-5.3.x-source-dir}/sapi ...

  9. Python学习(一):编写购物车

    1.购物车流程图: 2.代码实现: #!/usr/bin/env python #coding=utf-8 ChoiceOne =''' 1.查看余额 2.购物 3.退出 ''' ChoiceTwo ...

  10. UWP 使用OneDrive云存储2.x api(二)【全网首发】

    接上一篇 http://www.cnblogs.com/hupo376787/p/8032146.html 上一篇提到为了给用户打造一个完全无缝衔接的最佳体验,UWP开发者最好也要实现App设置和数据 ...