Java [Leetcode 190]Reverse Bits

题目描述：

everse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000).

解题思路：

移位操作。

代码如下：

public class Solution {
    // you need treat n as an unsigned value
    public int reverseBits(int n) {
        int res = 0;
        for(int i = 0; i < 32; i++){
        	res += n & 1;
        	if(i < 31)
        		res <<= 1;
        	n >>>= 1;
        }
        return res;
    }
}