【leetcode】986. Interval List Intersections
题目如下:
Given two lists of closed intervals, each list of intervals is pairwise disjoint and in sorted order.
Return the intersection of these two interval lists.
(Formally, a closed interval
[a, b]
(witha <= b
) denotes the set of real numbersx
witha <= x <= b
. The intersection of two closed intervals is a set of real numbers that is either empty, or can be represented as a closed interval. For example, the intersection of [1, 3] and [2, 4] is [2, 3].)Example 1:
Input: A = [[0,2],[5,10],[13,23],[24,25]], B = [[1,5],[8,12],[15,24],[25,26]]
Output: [[1,2],[5,5],[8,10],[15,23],[24,24],[25,25]]
Reminder: The inputs and the desired output are lists of Interval objects, and not arrays or lists.
解题思路:因为A与B的最大长度是1000,因此O(n^2)的时间复杂度是可以接受的。依次比较A与B中的所有元素,求出交集即可。
代码如下:
# Definition for an interval.
class Interval(object):
def __init__(self, s=0, e=0):
self.start = s
self.end = e class Solution(object):
def intervalIntersection(self, A, B):
"""
:type A: List[Interval]
:type B: List[Interval]
:rtype: List[Interval]
"""
res = []
for a in A:
for b in B:
if a.end < b.start:
break
elif a.start > b.end:
continue
else:
res.append(Interval(max(a.start,b.start),min(a.end,b.end)))
return res
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