Computer simulations often require random numbers. One way to generate pseudo-random numbers is via a function of the form

seed(x+1) = [seed(x) + STEP] % MOD

where '%' is the modulus operator.

Such a function will generate pseudo-random numbers (seed) between 0 and MOD-1. One problem with functions of this form is that they will always generate the same pattern over and over. In order to minimize this effect, selecting the STEP and MOD values carefully can result in a uniform distribution of all values between (and including) 0 and MOD-1.

For example, if STEP = 3 and MOD = 5, the function will generate the series of pseudo-random numbers 0, 3, 1, 4, 2 in a repeating cycle. In this example, all of the numbers between and including 0 and MOD-1 will be generated every MOD iterations of the function. Note that by the nature of the function to generate the same seed(x+1) every time seed(x) occurs means that if a function will generate all the numbers between 0 and MOD-1, it will generate pseudo-random numbers uniformly with every MOD iterations.

If STEP = 15 and MOD = 20, the function generates the series 0, 15, 10, 5 (or any other repeating series if the initial seed is other than 0). This is a poor selection of STEP and MOD because no initial seed will generate all of the numbers from 0 and MOD-1.

Your program will determine if choices of STEP and MOD will generate a uniform distribution of pseudo-random numbers.

InputEach line of input will contain a pair of integers for STEP and MOD in that order (1 <= STEP, MOD <= 100000). 
OutputFor each line of input, your program should print the STEP value right- justified in columns 1 through 10, the MOD value right-justified in columns 11 through 20 and either "Good Choice" or "Bad Choice" left-justified starting in column 25. The "Good Choice" message should be printed when the selection of STEP and MOD will generate all the numbers between and including 0 and MOD-1 when MOD numbers are generated. Otherwise, your program should print the message "Bad Choice". After each output test set, your program should print exactly one blank line. 
Sample Input

3 5
15 20
63923 99999

Sample Output

         3         5    Good Choice

        15        20    Bad Choice

     63923     99999    Good Choice

思路  : 水了两晚上的题,差点淹死.......这个题有两种做法,首先就是普通做法,其次就是求两个数最大公约数是不是一;

第一种方法:
#include<bits/stdc++.h>
using namespace std;
int main()
{
int s,mod,i;
while(~scanf("%d%d",&s,&mod))
{
int a[100001] = {0},seed=0;
while(!a[seed]){
a[seed] = 1;
seed = (seed+s)%mod;
}
for(i=0;i<mod;i++){
if(a[i] == 0){
printf("%10d%10d Bad Choice\n\n",s,mod);break;
}
}
if(i==mod){
printf("%10d%10d Good Choice\n\n",s,mod);
}
}
return 0;
}

  

第二种方法

#include <bits/stdc++.h>
using namespace std;
int main()
{
int step,mod1,t;
while(scanf("%d%d",&step,&mod1)==2)
{
printf("%10d%10d",step,mod1);
while(mod1)
{
t = step%mod1;
step = mod1;
mod1 = t;
}
printf(" %s\n\n",step == 1? "Good Choice":"Bad Choice");
}
return 0;
}

  欢迎批评指正。

Uniform Generator的更多相关文章

  1. HDU 1014:Uniform Generator

    Uniform Generator Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others ...

  2. Uniform Generator 分类: HDU 2015-06-19 23:26 11人阅读 评论(0) 收藏

    Uniform Generator Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) T ...

  3. uva 408 Uniform Generator

    Uniform Generator  Computer simulations often require random numbers. One way to generate pseudo-ran ...

  4. HDU 1014 Uniform Generator【GCD,水】

    Uniform Generator Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others ...

  5. HDU 1014 Uniform Generator(题解)

    Uniform Generator Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others ...

  6. HDU 1014 Uniform Generator(模拟和公式)

    传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1014 Uniform Generator Time Limit: 2000/1000 MS (Java ...

  7. (杭电 1014)Uniform Generator

    Uniform Generator Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)To ...

  8. HDOJ 1014 Uniform Generator(公约数问题)

    Problem Description Computer simulations often require random numbers. One way to generate pseudo-ra ...

  9. 1014 Uniform Generator

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission( ...

随机推荐

  1. dnsmasq详解&手册

    Dnsmasq为小型网络提供网络基础设施:DNS,DHCP,路由器通告和网络引导.它被设计为轻量级且占用空间小,适用于资源受限的路由器和防火墙.它还被广泛用于智能手机和便携式热点的共享,并支持虚拟化框 ...

  2. 虚拟机时间同步14 Aug 04:09:18 ntpdate[2941]: no server suitable for synchronization found

    因为虚拟机经常挂起,所以需要时间同步 [root@slave1 /root]$ cp /usr/share/zoneinfo/Asia/Shanghai /etc/localtime cp: over ...

  3. Net 4.5 WebSocket 在 Windows 7, Windows 8 and Server 2012上的比较

    .Net 4.5 WebSocket Server Running on Windows 7? Net 4.5 WebSocket Server 可以运行在 Windows 7,但是Net 4.5的 ...

  4. oracle导出序列的几种办法

    oracle导出序列的几种办法 注:本文来源于<oracle导出序列的几种办法> 方法一: select 'create sequence ' ||sequence_name|| ' mi ...

  5. Oracle存储过程中跳出循环的写法

    注:本文来源于: <  Oracle存储过程中跳出循环的写法   > Oracle存储过程中跳出循环的写法 记录exit和return的用法 1:exit用来跳出循环 loop IF V_ ...

  6. 尚硅谷《全套Java、Android、HTML5前端视频》

    尚硅谷<全套Java.Android.HTML5前端视频> (百万谷粉推荐:史上最牛.最适合自学的全套视频.资料及源码) [尚硅谷官网资料导航] 谷粒学院在线学习:http://www.g ...

  7. nginx安装编译参数

  8. 解决:sudo: pip: command not found

    1-问题:Ubuntu下执行sudo pip install package-name 出现 sudo: pip: command not found 的问题. 2-原因:编译sudo的时候加入了–w ...

  9. MySQL 5.7的多源复制

    MySQL 5.7已经开始支持了多源复制,相信小伙们都很激动,MySQL 5.7之前只能实现一主一从.一主多从或者多主多从的复制,如果想实现多主一从的复制,只好使用MariaDB,但是MariaDB又 ...

  10. 升级centos6.8内核

    1.查看默认版本:uname -r 2.更新nss 3.安装elrepo的yum源,升级内核需要使用elrepo的yum源,在安装yum源之前还需要我们导入elrepo的key rpm --impor ...