C# 历遍对象属性

今天有个网友问如何历遍对象的所有公共属性，并且生成XML。采用序列化方式的话比较简单，我写个手工解析的例子，这样能让初学者更加理解也比较灵活，记录一下吧或许会有人用到。

对象模型：

    public class Master
    {
        public string Description { get; set; }
        public List<Slave> Slaves { get; set; }
    }

    public class Slave
    {
        public int ID { get; set; }
        public string Name { get; set; }
    }

解析代码：

  //生成数据
  Master master = new Master();
  master.Description = "ABCD";
  master.Slaves = new List<Slave>();
  master.Slaves.Add(new Slave { Name = "aaa", ID =  });
  master.Slaves.Add(new Slave { Name = "bbb", ID =  });
  master.Slaves.Add(new Slave { Name = "ccc", ID =  });

  StringBuilder sb = new StringBuilder("<Root>\r\n");
  //生成XML
  foreach (PropertyInfo pi in master.GetType().GetProperties())
  {
      if (pi.PropertyType.IsGenericType)
      {
          sb.AppendLine($"<{pi.Name}>");
          foreach (object items in (pi.GetValue(master, null) as IEnumerable<object>))
          {
              sb.AppendLine($"<{items.GetType().Name}>");
              foreach (PropertyInfo item in items.GetType().GetProperties())
              {
                  sb.AppendLine($"<{item.Name}>{item.GetValue(items, null)}</{item.Name}>");
              }
              sb.AppendLine($"</{items.GetType().Name}>");
          }
          sb.AppendLine("</{pi.Name}>");
      }
      else
      {
          sb.AppendLine($"<{pi.Name}>{pi.GetValue(master, null)}</{pi.Name}>");
      }
  }
  sb.AppendLine("</Root>");
  MessageBox.Show(sb.ToString());

生成的XML结构：

<Root>
  <Description>ABCD</Description>
  <Slaves>
    <Slave>
      <ID>1</ID>
      <Name>aaa</Name>
    </Slave>
    <Slave>
      <ID>2</ID>
      <Name>bbb</Name>
    </Slave>
    <Slave>
      <ID>3</ID>
      <Name>ccc</Name>
    </Slave>
  </Slaves>
</Root>