Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next().


Here is an example. Assume that the iterator is initialized to the beginning of the list: [1, 2, 3].

Call next() gets you 1, the first element in the list.

Now you call peek() and it returns 2, the next element. Calling next() after that still return 2.

You call next() the final time and it returns 3, the last element. Calling hasNext() after that should return false.

Follow up: How would you extend your design to be generic and work with all types, not just integer?

Credits:
Special thanks to @porker2008 for adding this problem and creating all test cases.

给了一个迭代器Iterator类接口有next(),hasNext()方法,让在此基础上设计实现一个PeekingIterator,有如下函数:

peek():返回下一个元素,但指针不移动到下一个
next(): 移动到下一个元素x并返回x
hasNext() :返回有下一个元素

解法:为了能peek()后下次next()还得到同样的数字,要用一个缓存保存下一个数字。当peek()时,返回缓存里的数就行,迭代器位置不会变。当next()的时候除了要返回数字和指针移动一位,还要将缓存更新为下一个数字,如果没有下一个就将缓存更新为null。

Java:

class PeekingIterator implements Iterator<Integer> {
private Iterator<Integer> iter;
private Integer nextElement;
private boolean peekUsed; public PeekingIterator(Iterator<Integer> iterator) {
// initialize any member here.
iter = iterator;
} // Returns the next element in the iteration without advancing the iterator.
public Integer peek() {
if(!peekUsed) {
nextElement = iter.next();
peekUsed = true;
}
return nextElement;
} // hasNext() and next() should behave the same as in the Iterator interface.
// Override them if needed.
@Override
public Integer next() {
if(peekUsed) {
peekUsed = false;
return nextElement;
}
return iter.next();
} @Override
public boolean hasNext() {
if(peekUsed) {
return true;
}
return iter.hasNext();
}
}

Java:  用Integer来做global variable, 不用使用boolean

// Java Iterator interface reference:
// https://docs.oracle.com/javase/8/docs/api/java/util/Iterator.html
class PeekingIterator implements Iterator<Integer> {
private Iterator<Integer> iter;
private Integer next; public PeekingIterator(Iterator<Integer> iterator) {
// initialize any member here.
iter = iterator;
if (iter.hasNext()) {
next = iter.next();
}
} // Returns the next element in the iteration without advancing the iterator.
public Integer peek() {
return next;
} // hasNext() and next() should behave the same as in the Iterator interface.
// Override them if needed.
@Override
public Integer next() {
Integer res = next;
next = iter.hasNext() ? iter.next() : null;
return res;
} @Override
public boolean hasNext() {
return next != null;
}
}

Python:

class PeekingIterator(object):
def __init__(self, iterator):
"""
Initialize your data structure here.
:type iterator: Iterator
"""
self.iterator = iterator
self.val_ = None
self.has_next_ = iterator.hasNext()
self.has_peeked_ = False def peek(self):
"""
Returns the next element in the iteration without advancing the iterator.
:rtype: int
"""
if not self.has_peeked_:
self.has_peeked_ = True
self.val_ = self.iterator.next()
return self.val_; def next(self):
"""
:rtype: int
"""
self.val_ = self.peek()
self.has_peeked_ = False
self.has_next_ = self.iterator.hasNext()
return self.val_; def hasNext(self):
"""
:rtype: bool
"""
return self.has_next_   

C++:

// Below is the interface for Iterator, which is already defined for you.
// **DO NOT** modify the interface for Iterator.
class Iterator {
struct Data;
Data* data;
public:
Iterator(const vector<int>& nums);
Iterator(const Iterator& iter);
virtual ~Iterator();
// Returns the next element in the iteration.
int next();
// Returns true if the iteration has more elements.
bool hasNext() const;
}; class PeekingIterator : public Iterator {
public:
PeekingIterator(const vector<int>& nums) : Iterator(nums) {
// Initialize any member here.
// **DO NOT** save a copy of nums and manipulate it directly.
// You should only use the Iterator interface methods.
_flag = false;
} // Returns the next element in the iteration without advancing the iterator.
int peek() {
if (!_flag) {
_value = Iterator::next();
_flag = true;
}
return _value;
} // hasNext() and next() should behave the same as in the Iterator interface.
// Override them if needed.
int next() {
if (!_flag) return Iterator::next();
_flag = false;
return _value;
} bool hasNext() const {
if (_flag) return true;
if (Iterator::hasNext()) return true;
return false;
}
private:
int _value;
bool _flag;
};

  

All LeetCode Questions List 题目汇总

[LeetCode] 284. Peeking Iterator 瞥一眼迭代器的更多相关文章

  1. 【LeetCode】284. Peeking Iterator 解题报告(Python)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/peeking-i ...

  2. 【LeetCode】284. Peeking Iterator

    题目: Given an Iterator class interface with methods: next() and hasNext(), design and implement a Pee ...

  3. [LeetCode] 281. Zigzag Iterator 之字形迭代器

    Given two 1d vectors, implement an iterator to return their elements alternately. Example: Input: v1 ...

  4. 284. Peeking Iterator

    题目: Given an Iterator class interface with methods: next() and hasNext(), design and implement a Pee ...

  5. 设计模式 - 迭代模式(iterator pattern) Java 迭代器(Iterator) 详细解释

    迭代模式(iterator pattern) Java 迭代器(Iterator) 详细解释 本文地址: http://blog.csdn.net/caroline_wendy 參考迭代器模式(ite ...

  6. Java容器类源码分析之Iterator与ListIterator迭代器(基于JDK8)

    一.基本概念 迭代器是一个对象,也是一种设计模式,Java有两个用来实实现迭代器的接口,分别是Iterator接口和继承自Iterator的ListIterator接口.实现迭代器接口的类的对象有遍历 ...

  7. Collection接口都是通过Iterator()(即迭代器)来对Set和List遍历

    以下介绍接口: List接口:(介绍其下的两个实现类:ArrayList和LinkedList) ArrayList和数组非常类似,其底层①也用数组组织数据,ArrayList是动态可变数组. ① 底 ...

  8. [LeetCode] Peeking Iterator 顶端迭代器

    Given an Iterator class interface with methods: next() and hasNext(), design and implement a Peeking ...

  9. LeetCode OJ:Peeking Iterator(peeking 迭代器)

    Given an Iterator class interface with methods: next() and hasNext(), design and implement a Peeking ...

随机推荐

  1. 1220 Vue与Django前后端的结合

    目录 vue的安装 Vue前端的设置 页面的分布 后台数据的替换 css样式 Django的配置 国际化配置 axios插件安装 CORS跨域问题(同源策略) 处理跨域问题: cors插件 axios ...

  2. python通过LXML库读取xml命名空间

    xml实例版本: <a> <city:table xmlns:city="city"> <heilongjiang name="citys& ...

  3. Python开发应用-操作excel

    一. openpyxl读 95%的时间使用的是这个模块,目前excel处理的模块,只有这个还在维护 1.workBook workBook=openpyxl.load_workbook('path(. ...

  4. 20199301《Linux内核原理与分析》第十一周作业

    Linux Capability探索实验 一.实验描述 本实验中,将感受到linux capability功能在访问控制上的优势,掌握使用Capability达到遵守最小权限原则的目的,并分析linu ...

  5. C++对象内存模型1(堆栈模型)(转)

    对象内存模型 一. 栈(Stack) VS. 堆(heap) 栈 由系统自动管理,以执行函数为单位 空间大小编译时确定(参数+局部变量) 函数执行时,系统自动分配一个stack 函数执行结束时,系统立 ...

  6. modbus-poll和modbus-slave工具的学习使用——环境搭建

    在modbus的学习工具中,非modbus-poll和modbus-slave莫属了,在电脑上模拟的过程中,两者缺一不可 ,当然还需要虚拟串口工具:Configure Virtual Serial P ...

  7. Django 中使用redis

    Django使用redis   方式一,使用Django-redis模块 #安装: pip3 install django-redis CACHES = { "default": ...

  8. MATLAB中运算符优先级

    下述运算符的优先级从低到高: 1.先决或(||): 2.先决与(&&): 3.逻辑或(|): 4.逻辑与(&): 5.等于类(<,<=,>,>=,==, ...

  9. mybatis的判定时间字段问题 java.lang.IllegalArgumentException: invalid comparison: cn.hutool.core.date.DateTime and java.lang.String

    今天听组员说: mybatis在3.30版本及以上判定时间时 <if test="date_time != null and date_time != '' "> da ...

  10. 2-ESP8266 SDK开发基础入门篇--非RTOS版与RTOS版

    https://www.cnblogs.com/yangfengwu/p/11071580.html 所有的源码 https://gitee.com/yang456/Learn8266SDKDevel ...