最近遇到的C++数字和字符串的转换问题

1、

用itoa 和atoi  在头文件#include<cstidlib>

itoa用法：

char *  itoa ( int value, char * str, int base );

value
Value to be converted to a string.
str
Array in memory where to store the resulting null-terminated string.
base
Numerical base used to represent the value as a string, between  and , where  means decimal base,  hexadecimal,  octal, and  binary.

其中返回值和str是一样的。

atoi用法：

int atoi (const char * str);

/* atoi example */
#include <stdio.h>      /* printf, fgets */
#include <stdlib.h>     /* atoi */

int main ()
{
  int i;
  char buffer[];
  printf ("Enter a number: ");
  fgets (buffer, , stdin);
  i = atoi (buffer);
  printf ("The value entered is %d. Its double is %d.\n",i,i*);
  return ;
}

2、sprintf 在头文件#include<cstdio>

int sprintf ( char * str, const char * format, ... );
Return value:
On success, the total number of characters written is returned. This count does not include the additional null-character automatically appended at the end of the string.
On failure, a negative number is returned.

/* sprintf example */
#include <stdio.h>

int main ()
{
  char buffer [];
  int n, a=, b=;
  n=sprintf (buffer, "%d plus %d is %d", a, b, a+b);
  printf ("[%s] is a string %d chars long\n",buffer,n);
  return ;
}

3、字符串流的使用

头文件：#include<sstream>

stringstream strm; 　　　　　       创建自由的stringstream对象
stringstream strm(s);              创建存储s的副本的stringstream对象，其中s是string类型的对象
strm.str();　　　　　　　　　　       返回strm中存储打的string类型对象
strm.str(s);　　　　　　　　　      　将string类型的s复制给strm，返回void

string line，word；
while(ginline(cin，line))
{
     istringstrem strem(line)；
     while（strem >> word)
     {
            //do something
      }
}

class istream  可用来读取数据

class ostream 可用来写出数据

#include <sstream>
#include <iostream>
using namespace std;
int main ()
{

  int val1=, val2=;
  ostringstream format_message;
  format_message << "val1: " << val1 << endl
                   << "val2: " << val2 << endl;
  istringstream input_istring(format_message.str());
  cout << input_istring.str() << endl;
  cout << format_message.str() << endl;
  string dump;
   int val11,val22;
  input_istring >> dump >> val11 >> dump >> val22;

  cout << val11 << " " << val22 << endl;
  return ;
}