PAT1041: Be Unique
1041. Be Unique (20)
Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 104]. The first one who bets on a unique number wins. For example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.
Input Specification:
Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=105) and then followed by N bets. The numbers are separated by a space.
Output Specification:
For each test case, print the winning number in a line. If there is no winner, print "None" instead.
Sample Input 1:
7 5 31 5 88 67 88 17
Sample Output 1:
31
Sample Input 2:
5 888 666 666 888 888
Sample Output 2:
None 思路
和1084差不多的思路,队列q记录顺序,字典dic记录是否重复出现。遍历q的时候查下字典,输出第一个满足"仅出现一次"的数字即可。
代码
#include<iostream>
#include<map>
#include<iterator>
#include<queue>
using namespace std;
int main()
{
int N;
while(cin >> N)
{
map<int,int> dic;
queue<int> q;
for(int i = ;i < N;i++)
{
int value;
cin >> value;
if(dic.count(value) > )
dic[value] = -;
else
{
q.push(value);
dic.insert(pair<int,int>(value,));
}
} bool check = false;
while(!q.empty())
{
if(dic[q.front()] > )
{
check = true;
cout << q.front();
break;
}
q.pop();
}
if(!check)
cout << "None" << endl;
}
}
PAT1041: Be Unique的更多相关文章
- PAT-1041 Be Unique
Being unique is so important to people on Mars that even their lottery is designed in a unique way. ...
- pat1041. Be Unique (20)
1041. Be Unique (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Being uniqu ...
- [LeetCode] Unique Substrings in Wraparound String 封装字符串中的独特子字符串
Consider the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz" ...
- [LeetCode] Minimum Unique Word Abbreviation 最短的独一无二的单词缩写
A string such as "word" contains the following abbreviations: ["word", "1or ...
- [LeetCode] Count Numbers with Unique Digits 计算各位不相同的数字个数
Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Examp ...
- [LeetCode] Unique Word Abbreviation 独特的单词缩写
An abbreviation of a word follows the form <first letter><number><last letter>. Be ...
- [LeetCode] Unique Binary Search Trees 独一无二的二叉搜索树
Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For examp ...
- [LeetCode] Unique Binary Search Trees II 独一无二的二叉搜索树之二
Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For e ...
- [LeetCode] Unique Paths II 不同的路径之二
Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How m ...
随机推荐
- java工具类(三)之生成若干位随机数
java 生成若干位随机数的问题 在一次编程的过程中偶然碰到一个小问题,就是需要生成一个4位数的随机数,如果是一个不到4位大的数字,前面可以加0来显示.因为要求最后是一个4位的整数,不带小数点.当时就 ...
- libevent之Reactor模式
通过前边的一篇博文轻量级网络库libevent初探,我们知道libevent实际上是封装了不同操作系统下的/dev/poll.kqueue.event ports.select.poll和epoll事 ...
- 用简单的C语言实现多任务轮流切换(模拟操作系统线程机制)
最近在看linux内核的进程调度算法,也写了不少的内核注释,也参考了鸿哥的单片机框架,代码注释就开源在我的CSDN的git代码库里,有兴趣的可以去瞧瞧. 突发奇想,想到了既然单片机能够实现,那么我用标 ...
- Android性能优化之界面UI篇
1.使用style.color.string.dimen样式来分离xml布局文件,减少代码的重复使用,增加代码复用率,防止hardcode,下面是一个例子: 在定义layout时候,因为每个View或 ...
- Auto Create Editable Copy Font(Unity3D开发之二十二)
猴子原创,欢迎转载.转载请注明: 转载自Cocos2Der-CSDN,谢谢! 原文地址: http://blog.csdn.net/cocos2der/article/details/48318879 ...
- charles抓取https请求包
说明: 用charles抓取https请求,会出现SSL Proxying disabled in Proxy Settings这样的提示,如下图.要通过charles抓取数据,还需要进行一些简单的设 ...
- EBS-子库存转移和物料搬运单区别
FROM:http://bbs.erp100.com/forum.php?mod=viewthread&tid=261550&extra=page%3D7 EBS-子库存转移和物料搬运 ...
- The 11th tip of DB Query Analyzer
The 11th tip of DB Query Analyzer MA Gen feng ...
- spring-cloud-config安全问题
配置服务的安全问题会很重要,其中的内容是我自己学习的,由于学习时间不长,有可能不是很完备,如果有更好的方案,烦请评论中留言或私信,谢谢! 1. 首先访问配置服务需要设置密码: 使用spring-sec ...
- Spring Boot Kafka
1.创建集群 http://kafka.apache.org/documentation/#quickstart 有一句我觉得特别重要: For Kafka, a single broker is j ...