Cable master POJ - 1064
Inhabitants of the Wonderland have decided to hold a regional programming contest. The Judging Committee has volunteered and has promised to organize the most honest contest ever. It was decided to connect computers for the contestants using a “star” topology - i.e. connect them all to a single central hub. To organize a truly honest contest, the Head of the Judging Committee has decreed to place all contestants evenly around the hub on an equal distance from it.
To buy network cables, the Judging Committee has contacted a local network solutions provider with a request to sell for them a specified number of cables with equal lengths. The Judging Committee wants the cables to be as long as possible to sit contestants as far from each other as possible.
The Cable Master of the company was assigned to the task. He knows the length of each cable in the stock up to a centimeter,and he can cut them with a centimeter precision being told the length of the pieces he must cut. However, this time, the length is not known and the Cable Master is completely puzzled.
You are to help the Cable Master, by writing a program that will determine the maximal possible length of a cable piece that can be cut from the cables in the stock, to get the specified number of pieces.
Input
The first line of the input file contains two integer numb ers N and K, separated by a space. N (1 = N = 10000) is the number of cables in the stock, and K (1 = K = 10000) is the number of requested pieces. The first line is followed by N lines with one number per line, that specify the length of each cable in the stock in meters. All cables are at least 1 meter and at most 100 kilometers in length. All lengths in the input file are written with a centimeter precision, with exactly two digits after a decimal point.
Output
Write to the output file the maximal length (in meters) of the pieces that Cable Master may cut from the cables in the stock to get the requested number of pieces. The number must be written with a centimeter precision, with exactly two digits after a decimal point.
If it is not possible to cut the requested number of pieces each one being at least one centimeter long, then the output file must contain the single number “0.00” (without quotes).
Sample Input
4 11
8.02
7.43
4.57
5.39
Sample Output
2.00
//给你n段电缆,然后给出一个k代表要求从n段截取的段数
//然后让你从这n段电缆中截取等长度的电缆,问最大能截取的长度是多大
#include<string>
#include<stdio.h>
#include<iomanip>
#include<string.h>
#include<iostream>
#include<algorithm>
using namespace std;
typedef long long ll;
int n,k;
int a[10005];
int judge(int x)
{
int sum=0;
for(int i=0; i<n; i++)
sum+=a[i]/x;
if(sum>=k) return 1;
else return 0;
}
int main()
{
while(~scanf("%d%d",&n,&k))
{
for(int i=0; i<n; i++)
{
double f;
scanf("%lf",&f);
a[i]=(int)(f*100);
}
sort(a,a+n);
int high=a[n-1],low=1;
while(low<=high)
{
int mid=(low+high)>>1;
if(judge(mid)) low=mid+1;
else high=mid-1;
}
cout<<fixed<<setprecision(2)<<(double)high/100.0<<endl;//fixed 和 setpriecision 连用可以控制输出
}
return 0;
}
Cable master POJ - 1064的更多相关文章
- Divide and Conquer:Cable Master(POJ 1064)
缆绳大师 题目大意,把若干线段分成K份,求最大能分多长 二分法模型,C(x)就是题干的意思,在while那里做下文章就可以了,因为这个题目没有要求长度是整数,所以我们要不断二分才行,一般50-100次 ...
- (poj)1064 Cable master 二分+精度
题目链接:http://poj.org/problem?id=1064 Description Inhabitants of the Wonderland have decided to hold a ...
- POJ 1064 Cable master(二分查找+精度)(神坑题)
POJ 1064 Cable master 一开始把 int C(double x) 里面写成了 int C(int x) ,莫名奇妙竟然过了样例,交了以后直接就wa. 后来发现又把二分查找的判断条 ...
- poj 1064 Cable master 判断一个解是否可行 浮点数二分
poj 1064 Cable master 判断一个解是否可行 浮点数二分 题目链接: http://poj.org/problem?id=1064 思路: 二分答案,floor函数防止四舍五入 代码 ...
- 二分搜索 POJ 1064 Cable master
题目传送门 /* 题意:n条绳子问切割k条长度相等的最长长度 二分搜索:搜索长度,判断能否有k条长度相等的绳子 */ #include <cstdio> #include <algo ...
- POJ 1064 Cable master (二分)
题目链接: 传送门 Cable master Time Limit: 1000MS Memory Limit: 65536K 题目描述 有N条绳子,它们长度分别为Li.如果从它们中切割出K条长 ...
- [ACM] poj 1064 Cable master (二分查找)
Cable master Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 21071 Accepted: 4542 Des ...
- POJ 1064 Cable master
Cable master Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 37865 Accepted: 8051 Des ...
- poj 1064 Cable master【浮点型二分查找】
Cable master Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 29554 Accepted: 6247 Des ...
随机推荐
- 【BZOJ】4753: [Jsoi2016]最佳团体 01分数规划+树上背包
[题意]n个人,每个人有价值ai和代价bi和一个依赖对象ri<i,选择 i 时 ri 也必须选择(ri=0时不依赖),求选择k个人使得Σai/Σbi最大.n<=2500,ai,bi< ...
- 【BZOJ】3527: [Zjoi2014]力 FFT
[参考]「ZJOI2014」力 - FFT by menci [算法]FFT处理卷积 [题解]将式子代入后,化为Ej=Aj-Bj. Aj=Σqi*[1/(i-j)^2],i=1~j-1. 令f(i)= ...
- flex实例(阮一峰)
Flex 布局教程:实例篇 作者: 阮一峰 日期: 2015年7月14日 上一篇文章介绍了Flex布局的语法,今天介绍常见布局的Flex写法. 你会看到,不管是什么布局,Flex往往都可以几行命令 ...
- low逼三人组、nb二人组、归并、希尔排序----小结
- Automation Testing - Best Practice(书写规范)
Coding Standards Coding Standards are suggestions that will help us to write automation Scripts code ...
- 某线下赛AWD
拿别人比赛的来玩一下,或许这就是菜的力量吧. 0x01 任意文件读取: switch ($row['media_type']) { case 0: // 图片广告 ...... break; case ...
- docker安装总结 linux红帽系列
由于Docker限制分为两个版本CE和EE,所以之前yum里面的docker是老版本,需要先进行卸载,现在的包名叫做docker-ce yum remove docker docker-common ...
- POJ - Problem 1275 - Cashier Employment
· 对于差分约束,题目要求求什么便设什么,令$Sum[i]$表示由$0 ~ i$的雇佣人数. · 要充分利用题目所给条件,令$Have[i]$表示i时刻申报的人数,$Need[i]$表示i时刻需要的人 ...
- iOS 取消按钮高亮显示方法
objective-C 第1种方法: 设置按钮的normal 与 highlighted 一样的图片, 不过如果你也需要selected状态下的图片, 就不能这么做, 这样做在取消选中状态的时候就会显 ...
- caffe源码整个训练过程
Caffe源码 Blob protected: shared_ptr<SyncedMemory> data_; shared_ptr<SyncedMemory> diff_; ...