Golang 之 Base62 编码

Base62 编码用62个可见字符来编码信息，也就是所谓的62进制，可用于缩短地址之类的。实现起来也很简单。当然，这个实现跟别人家的有可能不一样，反正自己能编能解就行。

package main

import (
    "math"
    "strings"
)

const CODE62  = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
const CODE_LENTH =
var EDOC = map[string]int{"":,"":,"":,"":,"":,"":,"":,"":,"":,"":,"a":,"b":,"c":,"d":,"e":,"f":,"g":,"h":,"i":,"j":,"k":,"l":,"m":,"n":,"o":,"p":,"q":,"r":,"s":,"t":,"u":,"v":,"w":,"x":,"y":,"z":,"A":,"B":,"C":,"D":,"E":,"F":,"G":,"H":,"I":,"J":,"K":,"L":,"M":,"N":,"O":,"P":,"Q":,"R":,"S":,"T":,"U":,"V":,"W":,"X":,"Y":,"Z":, }

/**
 * 编码 整数 为 base62 字符串
 */
func Encode(number int) string {
    if number ==  {
        return ""
    }
    result := make([]byte , )
    for number >  {
        round  := number / CODE_LENTH
        remain := number % CODE_LENTH
        result = append(result,CODE62[remain])
        number  = round
    }
    return string(result)
}

/**
 * 解码字符串为整数
 */
func Decode(str string) int {
    str = strings.TrimSpace(str)
    var result int =
    for index,char := range []byte(str){
        result +=  EDOC[string(char)] * int(math.Pow(CODE_LENTH,float64(index)))
    }
    return result
}

里面硬编码了 CODE_LENGTH 是不想每次去算一下长度，省点时间。