获取url中？后面传递的参数

 function  getUrlArgs(){
             var url=location.href;
             var i=url.indexOf('?');
             if(i==-1)return;
             var querystr=url.substr(i+1);
             var arr1=querystr.split('&');
             var arr2=new Object();
             for (i in arr1){
                 var t=arr1[i].split('=');
                 arr2[t[0]]=t[1];
             }
             return arr2;
 }