android 复杂的json数据解析

1、通过谷歌的Gson来进行解析： 
json数据：sTotalString = {"message":"success","result":[{"surveyid":"1","surveyname":"B"}{surveyid":"2","surveyname":"C"}]};

public class SurveyVO {

    private String surveyId;
    private String surveyName;
    private String message;

    public String getMessage() {
        return message;
    }

    public void setMessage(String message) {
        this.message = message;
    }

    public String getSurveyId() {
        return surveyId;
    }

    public void setSurveyId(String surveyId) {
        this.surveyId = surveyId;
    }

    public String getSurveyName() {
        return surveyName;
    }

    public void setSurveyName(String surveyName) {
        this.surveyName = surveyName;
    }

}

public class SurveyListVO {

    private String message;
    private List<SurveyVO> result;
    public String getMessage() {
        return message;
    }
    public void setMessage(String message) {
        this.message = message;
    }
    public List<SurveyVO> getResult() {
        return result;
    }
    public void setResult(List<SurveyVO> result) {
        this.result = result;
    }
}

json格式转换成object类型：

public class fromGson() {
        sTotalString = {"message":"success","result":[{"surveyid":"1","surveyname":"B"}{"surveyid":"2","surveyname":"C"}]};

        Gson gson = new Gson();
        SurveyListVO surveyListVO = gson.fromJson(sTotalString,
                                    SurveyListVO.class);
        for (int i = 0; i < surveyListVO.getResult().size(); i++) {
            System.out.print(surveyListVO.getResult().get(i)
                             .getSurveyId());
            print: 1////
            System.out.print(surveyListVO.getResult().get(i)
                             .getSurveyName());
            print: B///C
            System.out.print(surveyListVO.getMessage());
        }
    }

2、通过json-org.jar包进行解析： 
json数据：sTotalString = {"message":"success","result":[{"surveyid":"1","surveyname":"B"}{surveyid":"2","surveyname":"C"}]};

public class SurveyVO {
    private String surveyId;
    private String surveyName;
    public String getSurveyId() {
        return surveyId;
    }
    public void setSurveyId(String surveyId) {
        this.surveyId = surveyId;
    }
    public String getSurveyName() {
        return surveyName;
    }
    public void setSurveyName(String surveyName) {
        this.surveyName = surveyName;
    }
}

json格式转换成object类型：

public class fromJson() {
        sTotalString = {"message":"success","result":[{"surveyid":"1","surveyname":"B"}{"surveyid":"2","surveyname":"C"}]};
        JSONObject json;

        try {
            json = new JSONObject(sTotalString);
            JSONArray results = json.getJSONArray("result");
            for (int i = 0; i < results.length(); i++) {
                SurveyVO surveyVO = new SurveyVO();
                JSONObject result = results.getJSONObject(i);
                System.out.println(result.getString("surveyId")+" "+result.getString("surveyName"));
                surveyVO.setSurveyId(result.getString("surveyId"));
                surveyVO.setSurveyName(result.getString("surveyName"));
                surveyVOList.add(surveyVO);
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }