B. Andrey and Problem
time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Andrey needs one more problem to conduct a programming contest. He has n friends who are always willing to help. He can ask some of them to come up with
a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.

Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of
Andrey not getting upset.

Input

The first line contains a single integer n (1 ≤ n ≤ 100) —
the number of Andrey's friends. The second line contains n real numbers pi(0.0 ≤ pi ≤ 1.0) —
the probability that the i-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.

Output

Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10 - 9.

Sample test(s)
input
4
0.1 0.2 0.3 0.8
output
0.800000000000
input
2
0.1 0.2
output
0.260000000000
Note

In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.

In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26.


Codeforces Round #253 (Div. 1) B. Andrey and Problem的更多相关文章

  1. Codeforces Round #253 (Div. 2) D. Andrey and Problem

    关于证明可以参考题解http://codeforces.com/blog/entry/12739 就是将概率从大到小排序然后,然后从大到小计算概率 #include <iostream> ...

  2. Codeforces Round 253 (Div. 2)

    layout: post title: Codeforces Round 253 (Div. 2) author: "luowentaoaa" catalog: true tags ...

  3. Codeforces Round #253 (Div. 1) (A, B, C)

    Codeforces Round #253 (Div. 1) 题目链接 A:给定一些牌,然后如今要提示一些牌的信息,要求提示最少,使得全部牌能够被分辨出来. 思路:一共2^10种情况,直接暴力枚举,然 ...

  4. Codeforces Round #253 (Div. 2) D题

    题目大意是选出一个其他不选,问问最大概率: 刚开始想到DP:F[I][J][0]:表示从 前I个中选出J个的最大值, 然后对于F[I][J][1]=MAX(F[I-1][J][1],F[I-1][J- ...

  5. Codeforces Round #253 (Div. 1) A. Borya and Hanabi 暴力

    A. Borya and Hanabi Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/442/p ...

  6. Codeforces Round #253 (Div. 2) B - Kolya and Tandem Repeat

    本题要考虑字符串本身就存在tandem, 如测试用例 aaaaaaaaabbb 3 输出结果应该是8而不是6,因为字符串本身的tanderm时最长的 故要考虑字符串本身的最大的tanderm和添加k个 ...

  7. Codeforces Round #253 (Div. 2) A. Anton and Letters

    题目很简单,只需要注意带空格的输入用getline即可 #include <iostream> #include <vector> #include <algorithm ...

  8. Codeforces Round #253 (Div. 2), problem: (B)【字符串匹配】

    简易字符串匹配,题意不难 #include <stdio.h> #include <string.h> #include <math.h> #include < ...

  9. Codeforces Round #253 (Div. 2)B(暴力枚举)

    就暴力枚举所有起点和终点就行了. 我做这题时想的太多了,最简单的暴力枚举起始点却没想到...应该先想最简单的方法,层层深入. #include<iostream> #include< ...

随机推荐

  1. MySQL 关闭FOREIGN_KEY_CHECKS检查

    SET FOREIGN_KEY_CHECKS=0; truncate table QRTZ_BLOB_TRIGGERS; truncate table QRTZ_CALENDARS; truncate ...

  2. RAC 备份到本地不同设备

  3. Andy&#39;s First Dictionary

    Description Andy, 8, has a dream - he wants to produce his very own dictionary. This is not an easy ...

  4. delphi cmd(4个例子都是通过管道取得)

    //K8执行DOS并返回结果 function RunDosCommand(Command: string): string; var hReadPipe: THandle; hWritePipe:  ...

  5. AIX下RAC搭建 Oracle10G(四)安装CRS

    AIX下RAC搭建系列 AIX下RAC搭建Oracle10G(四)安装CRS 环境 节点 节点1 节点2 小机型号 IBM P-series 630 IBM P-series 630 主机名 AIX2 ...

  6. [Cocos2d-x]布局与定位

    游戏中,精灵的位置由Position与AnchorPoint同时决定. Scene 锚点 (0,0) 不启用锚点 CCNode锚点 (0,0) 不启用锚点  CCLayer锚点 (0,0) 不启用锚点 ...

  7. 在VM已安装Android4.4 连接小米手环 网络设置

    1.打开一个终端 2.输入su,选择同意 watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvbGl5dW4xMjNneA==/font/5a6L5L2T/fon ...

  8. 性能测试开源小工具——http_load介绍

    淘测试 性能测试开源小工具——http_load介绍 meizhu 发表于:2009-07-02 浏览:3552次 评论:1次 所属分类: 性能测试 性能测试开源小工具——http_load介绍 ht ...

  9. 2014-5-22 java.lang.OutOfMemoryError: Java heap space的一次诊断

    收到消息某系统一个节点因为内存溢出而宕机.系统的中间件是weblogic.数据库的oracle. 1. 先用IBM  HeapAnalyzer分析内存溢出时的dump文件,找到占用内存最多的请求,然后 ...

  10. [华为机试练习题]50.求M的N次方的最后三位

    题目 描写叙述: 正整数M 的N次方有可能是一个很大的数字,我们仅仅求该数字的最后三位 例1: 比方输入5和3 ,5的3次方为125.则输出为125 例2: 比方输入2和10 2的10次方为1024 ...