hdu 5077 NAND(暴力打表)

题目链接：hdu 5077 NAND

题目大意：Xiaoqiang要写一个编码程序，然后依据x1，x2，x3的值构造出8个字符。如今给定要求生成的8个字符。问

说Xiaoqiang最少要写多少行代码。代码内容仅仅能为NAND操作和return操作，操作的变量能够是常数。

解题思路：输入总共就256中情况，所以暴力剪枝打表，打表的代码手贱给删了。。。所以就将一下思路。开一个s数组

表示变量，然后相应每一层每次两个变量进行NAND操作。

大致三个剪枝，dfs时候，变量出现同样就跳过。8个字符能够直接依据数的位运算计算；单前层出现同样的跳过。

#include <cstdio>
#include <cstring>
#include <algorithm>

using namespace std;

const int ans[300] = {1, 5, 6, 3, 6, 3, 7, 4, 7, 8, 4, 5, 4, 5, 4, 1, 6, 3, 7, 4, 7, 4, 9, 7, 8, 8, 7, 5, 7, 5, 7, 4, 7, 8, 4, 5, 8, 8, 7, 5, 8, 9, 5, 6, 8, 8, 5, 5, 4, 5, 4, 1, 7, 5, 7, 4, 8, 8, 5, 5, 5, 7, 6, 4, 7, 8, 8, 8, 4, 5, 7, 5, 8, 9, 8, 8, 5, 6, 5, 5, 4, 5, 7, 5, 4, 1, 7, 4, 8, 8, 5, 7, 5, 5, 6, 4, 8, 9, 8, 8, 8, 8, 5, 7, 11, 9, 8, 9, 8, 9, 8, 8, 5, 6, 5, 5, 5, 5, 6, 4, 8, 9, 8, 8, 8, 8, 8, 7, 8, 9, 9, 9, 9, 9, 10, 9, 5, 7, 6, 6, 6, 6, 7, 6, 9, 9, 10, 9, 10, 9, 10, 10, 7, 6, 7, 7, 7, 7, 9, 7, 5, 7, 6, 6, 7, 6, 7, 7, 5, 6, 2, 3, 6, 6, 4, 3, 6, 6, 7, 6, 7, 7, 9, 7, 6, 6, 4, 3, 7, 7, 7, 6, 5, 7, 7, 6, 6, 6, 7, 7, 5, 6, 6, 6, 2, 3, 4, 3, 6, 6, 7, 7, 7, 6, 9, 7, 6, 6, 7, 7, 4, 3, 7, 6, 5, 6, 6, 6, 6, 6, 7, 7, 8, 9, 5, 6, 5, 6, 2, 5, 2, 3, 4, 3, 4, 3, 7, 6, 5, 6, 2, 5, 2, 5, 4, 1};

int main () {
    int cas;
    char p[10];
    scanf("%d", &cas);
    while (cas--) {
        scanf("%s", p);
        int ret = 0;
        for (int i = 0; i < 8; i++)
            ret = ret * 2 + p[i] - '0';
        printf("%d\n", ans[ret]);
    }

    return 0;
}

版权声明：本文博主原创文章。博客，未经同意不得转载。