Codeforces Round #366 (Div. 2) A
1 second
256 megabytes
standard input
standard output
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have n layers. The first layer is hate, second one is love, third one is hate and so on...
For example if n = 1, then his feeling is "I hate it" or if n = 2 it's "I hate that I love it", and if n = 3 it's "I hate that I love that I hate it" and so on.
Please help Dr. Banner.
The only line of the input contains a single integer n (1 ≤ n ≤ 100) — the number of layers of love and hate.
Print Dr.Banner's feeling in one line.
1
I hate it
2
I hate that I love it
3
I hate that I love that I hate it
题意:水题
题解:取模输出
/******************************
code by drizzle
blog: www.cnblogs.com/hsd-/
^ ^ ^ ^
O O
******************************/
//#include<bits/stdc++.h>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<map>
#include<algorithm>
#include<queue>
#include<cmath>
#define ll __int64
#define PI acos(-1.0)
#define mod 1000000007
using namespace std;
int n;
int main()
{
scanf("%d",&n);
for(int i=;i<=n;i++)
{
if(i%==)
cout<<"I hate";
if(i%==)
cout<<"I love";
if(i!=n)
cout<<" that ";
if(i==n)
cout<<" it"<<endl;
}
return ;
}
Codeforces Round #366 (Div. 2) A的更多相关文章
- Codeforces Round #366 (Div. 2) ABC
Codeforces Round #366 (Div. 2) A I hate that I love that I hate it水题 #I hate that I love that I hate ...
- Codeforces Round #366 Div.2[11110]
这次出的题貌似有点难啊,Div.1的Standing是这样的,可以看到这位全站排名前10的W4大神也只过了AB两道题. A:http://codeforces.com/contest/705/prob ...
- Codeforces Round #366 (Div. 2)
CF 复仇者联盟场... 水题 A - Hulk(绿巨人) 输出love hate... #include <bits/stdc++.h> typedef long long ll; co ...
- Codeforces Round #366 (Div. 2) B
Description Peter Parker wants to play a game with Dr. Octopus. The game is about cycles. Cycle is a ...
- Codeforces Round #366 (Div. 2) C 模拟queue
C. Thor time limit per test 2 seconds memory limit per test 256 megabytes input standard input outpu ...
- Codeforces Round #366 (Div. 2) B 猜
B. Spider Man time limit per test 2 seconds memory limit per test 256 megabytes input standard input ...
- Codeforces Round #366 (Div. 2) C Thor(模拟+2种stl)
Thor 题意: 第一行n和q,n表示某手机有n个app,q表示下面有q个操作. 操作类型1:app x增加一条未读信息. 操作类型2:一次把app x的未读信息全部读完. 操作类型3:按照操作类型1 ...
- Codeforces Round #366 (Div. 2)_B. Spider Man
B. Spider Man time limit per test 2 seconds memory limit per test 256 megabytes input standard input ...
- Codeforces Round #366 (Div. 2)_C. Thor
C. Thor time limit per test 2 seconds memory limit per test 256 megabytes input standard input outpu ...
随机推荐
- 网页优化URI(http URI scheme与data URI scheme)
网页优化的一大首要任务是减少HTTP 请求 (http request) 的次数,例如通过合并多个JS文件,合并CSS样式文件.除此之外,还有一个data URL 的密技,让我们直接把图像的内容崁入网 ...
- ZOJ 3646 Matrix Transformer 二分匹配,思路,经典 难度:2
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=4836 因为要使对角线所有元素都是U,所以需要保证每行都有一个不同的列上有U,设 ...
- Servlet、MySQL中文乱码
1.Servlet中文乱码: 在doPost或doGet方法里,加上以下两行即可: response.setContentType("text/html;charset=UTF-8" ...
- javascript作用域(Scope),简述上下文(context)和作用域的定义
网页制作Webjx文章简介:这篇文章将正面解决这个问题:简述上下文(context)和作用域的定义,分析可以让我们掌控上下文的两种方法,最后深入一种高效的方案,它能有效解决我所碰到的90%的问题. 作 ...
- auto_ptr的使用原则
auto_ptr是c++标准库中的一种严格所有权型的智能指针,实现在backward/auto_ptr.h文件中 pro: 1.做临时变量时,不需要手动去释放资源 void f() { ClassA ...
- CCNA 4.14 TP Correction
All people seem to need data processing ( Application presentation session transport network data li ...
- Linux下screen命令
//1.列出当前的screenscreen -ls //2.新建一个screen,直接在命令行键入screen命令 screen -S [会话名称][root@www.lnuxidc.com ~]# ...
- 黑马程序员——OC语言Foundation框架 结构体
Java培训.Android培训.iOS培训..Net培训.期待与您交流! (以下内容是对黑马苹果入学视频的个人知识点总结) (一)结构体 NSRange(location length) NSPoi ...
- cf--2A
//Accepted 100 KB 92 ms //模拟 #include <cstdio> #include <cstring> #include <iostream& ...
- Oracle普通索引,唯一索引,主键的区别
索引是我们经常使用的一种数据库优化手段,适当的业务操作场景使用适当的索引方案,可以显著的提升系统整体查询性能,当然用户体验也随之提高. 在Oracle中,唯一性索引(Unique Index)是我们经 ...