Question

Write a function to find the longest common prefix string amongst an array of strings.

Solution

第一思路是用Trie,但是对于一道Easy类别的题目,用Trie显然是杀鸡用牛刀。

于是我们可以参考到构造Trie的过程,来找这个最长prefix。

我们先用String array中第一个String初始化Pre,然后遍历剩下的每一个String,找重合的终点,删除不重合的部分。

 public class Solution {
public String longestCommonPrefix(String[] strs) {
if (strs == null || strs.length < 1) {
return "";
}
int length = strs.length;
int initLen = strs[0].length();
StringBuilder result = new StringBuilder(initLen);
for (int i = 0; i < initLen; i++) {
result.append(strs[0].charAt(i));
}
for (int i = 1; i < length; i++) {
String curString = strs[i];
initLen = result.length();
for (int j = 0; j < initLen; j++) {
if (j < curString.length() && curString.charAt(j) == result.charAt(j)) {
continue;
}
result.delete(j, initLen);
break;
}
}
return result.toString();
}
}

更简单的方法是用String.indexOf()的方法来判断重合终点。

 public class Solution {
public String longestCommonPrefix(String[] strs) {
if (strs == null || strs.length < 1) {
return "";
}
int length = strs.length;
int initLen = strs[0].length();
String prev = strs[0];
for (int i = 0; i < length; i++) {
String curString = strs[i];
while (curString.indexOf(prev) != 0) {
prev = prev.substring(0, prev.length() - 1);
}
}
return prev;
}
}

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