Poj 3030 Nasty Hacks
1.Link:
http://poj.org/problem?id=3030
2.Content:
Nasty Hacks
Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 12350 Accepted: 8537 Description
![]()
You are the CEO of Nasty Hacks Inc., a company that creates small pieces of malicious software which teenagers may use to fool their friends. The company has just finished their first product and it is time to sell it. You want to make as much money as possible and consider advertising in order to increase sales. You get an analyst to predict the expected revenue, both with and without advertising. You now want to make a decision as to whether you should advertise or not, given the expected revenues.
Input
The input consists of n cases, and the first line consists of one positive integer giving n. The next n lines each contain 3 integers, r, e and c. The first, r, is the expected revenue if you do not advertise, the second, e, is the expected revenue if you do advertise, and the third, c, is the cost of advertising. You can assume that the input will follow these restrictions: −106 ≤ r, e ≤ 106 and 0 ≤ c ≤ 106.
Output
Output one line for each test case: “advertise”, “do not advertise” or “does not matter”, presenting whether it is most profitable to advertise or not, or whether it does not make any difference.
Sample Input
3
0 100 70
100 130 30
-100 -70 40Sample Output
advertise
does not matter
do not advertiseSource
3.Method:
4.Code:
#include<iostream>
using namespace std;
int main()
{
int i,n;
int r,e,c;
int result;
cin>>n;
for(i=;i<n;i++)
{
cin>>r>>e>>c;
result=e-c-r;
if(result>) cout<<"advertise"<<endl;
else if(result<) cout<<"do not advertise"<<endl;
else cout<<"does not matter"<<endl;
}
//system("pause");
return ; }
5.Reference:
Poj 3030 Nasty Hacks的更多相关文章
- HDOJ 2317. Nasty Hacks 模拟水题
Nasty Hacks Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Tota ...
- HDOJ(HDU) 2317 Nasty Hacks(比较、)
Problem Description You are the CEO of Nasty Hacks Inc., a company that creates small pieces of mali ...
- Nasty Hacks <入门练手题>
Nasty Hacks Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total S ...
- HDU 2317 Nasty Hacks
Nasty Hacks Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Tota ...
- 【转】POJ百道水题列表
以下是poj百道水题,新手可以考虑从这里刷起 搜索1002 Fire Net1004 Anagrams by Stack1005 Jugs1008 Gnome Tetravex1091 Knight ...
- POJ解题经验交流
感谢范意凯.陈申奥.庞可.杭业晟.王飞飏.周俊豪.沈逸轩等同学的收集整理. 题号:1003 Hangover求1/2+1/3+...1/n的和,问需多少项的和能超过给定的值 类似于Zerojudg ...
- 算法之路 level 01 problem set
2992.357000 1000 A+B Problem1214.840000 1002 487-32791070.603000 1004 Financial Management880.192000 ...
- hdu2317Nasty Hacks
Problem Description You are the CEO of Nasty Hacks Inc., a company that creates small pieces of mali ...
- dir命令只显示文件名
dir /b 就是ls -f的效果 1057 -- FILE MAPPING_web_archive.7z 2007 多校模拟 - Google Search_web_archive.7z 2083 ...
随机推荐
- 深入MySQL源码 学习方法 何登成专家
MYSQL 技术圈 有哪些做得好,又注重分享的公司: Oracle MySQL, MariaDB, Percona,Google, FB, Twitter, Taobao, NetEase… 有哪些值 ...
- unity工程接入Android sdk后真机测试解锁屏后退出的解决
unity工程接入如91.移动支付等Android sdk后,真机运行尤其是在4.0+以上坏境,往往会出现解锁屏后退出的情况,解决办法如下: 可以在AndroidManifest.xml中所有的con ...
- Line Search and Quasi-Newton Methods
Gradient Descent 机器学习中很多模型的参数估计都要用到优化算法,梯度下降是其中最简单也用得最多的优化算法之一.梯度下降(Gradient Descent)[3]也被称之为最快梯度(St ...
- 实例源码--Android自定义Gallery动画效果
相关文档与源码: 下载源码 技术要点: 1.自定义控件的使用 2.Gallery控件的使用实例 3.详细的源码注释 ...... 详细介绍: 1.自定义控件的使用 本套源码通过自定义控件的方式,继 ...
- [小技巧]兼容IE6的纯CSS背景半透明文字不透明
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...
- JSONP(处理跨域问题)
Ajax直接请求普通文件存在跨域无权限访问的问题 凡是拥有"src"这个属性的标签都拥有跨域的能力,比如<script>.<img>.<iframe& ...
- 关于 error: LNK1123: failure during conversion to COFF: file invalid or corrupt 错误的解决方案【Qt】【 VS2010】
近日因为换装硬盘重装了系统,于是不得不重新安装VS2010 Qt 这些个开发工具.安装过程都没什么问题,安装完了顺手点了个例子测试下好没好用,于是就出现了标题中的错误提示.之前处理过一次,时间久了就忘 ...
- 网站安全通用防护代码(C#版本源码提供)
每一个开发者都会意识到,网站发布之前,需要进行安全检查. 那么如何拦截攻击者注入恶意代码?如何防御诸如跨站脚本攻击(XSS).SQL注入攻击等恶意攻击行为? 针对目前常见的一些安全问题,结合目前一些常 ...
- Xcode 只有iOS device一个选项的解决办法
下载了一个demo准备研究发现只有iOS device,没有其他的机型可选,解决方法比较简单,调下iOS SDK就行了
- [改善Java代码]避免对象的浅拷贝
建议43: 避免对象的浅拷贝 我们知道一个类实现了Cloneable接口就表示它具备了被拷贝的能力,如果再覆写clone()方法就会完全具备拷贝能力.拷贝是在内存中进行的,所以在性能方面比直接通过ne ...