【习题 4-2 Uva201】Squares

【链接】 我是链接,点我呀:)

【题意】

在这里输入题意

【题解】

注意那个星号的数量。。。
然后V x y的话,是从(y,x)向(y+1,x)连线。
H x y才是从(x,y)向(x,y+1)连线
枚举以(x,y)作为左上角的举行就ok了

【代码】

#include <bits/stdc++.h>
using namespace std;

const int N = 10;

int n,m;
bool a[N+10][N+10][2];
int cnt[N+5];

bool check(int x,int y,int p){
    for (int i = 1;i <= p;i++)
        if (a[x][y][0]){
            y++;
            if (y>n) break;
        }else return 0;

    for (int i = 1;i <= p;i++)
        if (a[x][y][1]){
            x++;
            if (x>n) break;
        }else return 0;

    for (int i = 1;i <= p;i++)
        if (y-1>=1 && a[x][y-1][0]){
            y--;
            if (y<1) break;
        }else return 0;

    for (int i = 1;i <= p;i++)
        if (x-1>=1 && a[x-1][y][1]){
            x--;
            if (x<1) break;
        }else return 0;
    return 1;
}

int main(){
    //freopen("/home/ccy/rush.txt","r",stdin);
    //freopen("/home/ccy/rush_out.txt","w",stdout);
    ios::sync_with_stdio(0),cin.tie(0);
    int kase = 0;
    while (cin >> n){
        if (kase>0){
            cout<<endl;
            cout<<"**********************************"<<endl;
            cout<<endl;
        }
        cout<<"Problem #"<<++kase<<endl<<endl;
        memset(a,0,sizeof a);
        memset(cnt,0,sizeof cnt);
        cin >> m;
        for (int i = 1;i <= m;i++){
            char s[5];int x,y;
            cin >> s >> x >> y;

            if (s[0]=='H')
                a[x][y][0] = 1;
            else{
                swap(x,y);
                a[x][y][1] = 1;
            }
        }
        for (int p = 1;p <= n;p++)
            for (int i = 1;i <= n;i++)
                for (int j = 1;j <= n;j++)
                    if (check(i,j,p))
                        cnt[p]++;
        bool none = 1;
        for (int i = 1;i <= n;i++){
            if (cnt[i]>0) {
                none = 0;
                cout<<cnt[i]<<" square (s) of size "<<i<<endl;
            }

        }
        if (none) cout<<"No completed squares can be found."<<endl;
    }
    return 0;
}