hdu_2054_A == B_201311301601

A == B ?

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 53634    Accepted Submission(s): 8215

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

 

Input

each test case contains two numbers A and B.

 

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

 

Sample Input

1 2

2 2

3 3

4 3

 

Sample Output

NO

YES

YES

NO

 

 #include <stdio.h>
 #include <string.h>
 #define MAX 100000

 char str1[MAX+],str2[MAX+];
 int a1[MAX+],a2[MAX+],b1[MAX+],b2[MAX+];

 int bijiao(char *str1,char *str2)
 {
     int len1,len2;
         int i,j,k,t;
         for(i=;i<MAX+;i++)
         a1[i]=a2[i]=b1[i]=b2[i]=;
         len1=strlen(str1);
         for(i=;i<len1;i++)
         if(str1[i]=='.')
         {t=i;break;}
         if(i>=len1)
         t=len1;
         for(j=,i=t-;i>=;i--)
         a1[j++]=str1[i]-'';
         for(j=,i=t+;i<len1;i++)
         a2[j++]=str1[i]-'';
         len2=strlen(str2);
         for(i=;i<len2;i++)
         if(str2[i]=='.')
         {t=i;break;}
         if(i>=len2)
         t=len2;
         for(j=,i=t-;i>=;i--)
         b1[j++]=str2[i]-'';
         for(j=,i=t+;i<len2;i++)
         b2[j++]=str2[i]-'';
         if(len1==&&len2==)
         return ;
         for(i=;i<MAX;i++)
         {
             if(a1[i]!=||a2[i]!=||b1[i]!=||b2[i]!=)
             break;
         }
         if(i>=MAX)
         return ;
         for(i=;i<MAX;i++)
         {
             if(a1[i]!=b1[i])
             {
                 k=;
                 break;
             }
         }
         if(i>=MAX)
         {
             for(i=;i<MAX;i++)
             {
                 if(a2[i]!=b2[i])
                 {
                     k=;
                     break;
                 }
             }
             if(i>=MAX)
             k=;
         }
         return k;
         //puts(str1);
         //puts(str2);
 }
 int main()
 {
     while(scanf("%s%s",str1,str2)!=EOF)
     {
         int t=,k;
         //gets(str2);
         //getchar();
         if((str1[]>=''&&str1[]<='')&&(str2[]>=''&&str2[]<=''))
         k=bijiao(str1,str2);
         else if((str1[]>=''&&str1[]<='')&&(str2[]=='+'))
         k=bijiao(str1,str2+);
         else if((str2[]>=''&&str2[]<='')&&(str1[]=='+'))
         k=bijiao(str1+,str2);
         else if(str1[]==str2[])
         k=bijiao(str1+,str2+);
         else
         {
             t=bijiao(str1+,str2+);
             if(t==)
             k=;
             else
             k=;
         }
         if(k)
         printf("YES\n");
         else
         printf("NO\n");
     }
     return ;
 }

wa了n次，原来是数组开的太小