软通动力C语言机试题

 #include <stdio.h>

 int charCount(char *str)
 {
     int iCount = 0;
     int i, j, k=0;
     char *p = str;
     char *q = p;
     while (*p)
     {
         p++;
         k++;
     }
     for (i=0; i<128; i++)
     {
         str = q;
         for (j=0; j<k; j++)
         {
             if (i == *str)
             {
                 iCount++;
                 break;
             }
             str++;
         }
     }
     return iCount;
 }

 int main()
 {
     char *p = "   abcdeef121";
     printf("%d\n", charCount(p));
     return 0;
 }

实现统计一个字符串所含的不同字符的总数.比较简单,但是这个确实是考验你的基础扎实与否.