2016大连网络赛 Football Games
Football Games
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
mysterious country will hold a football world championships---Abnormal
Cup, attracting football teams and fans from all around the world. This
country is so mysterious that none of the information of the games will
be open to the public till the end of all the matches. And finally only
the score of each team will be announced.
At the first phase of the championships, teams are divided into M
groups using the single round robin rule where one and only one game
will be played between each pair of teams within each group. The winner
of a game scores 2 points, the loser scores 0, when the game is tied
both score 1 point. The schedule of these games are unknown, only the
scores of each team in each group are available.
When those
games finished, some insider revealed that there were some false scores
in some groups. This has aroused great concern among the pubic, so the
the Association of Credit Management (ACM) asks you to judge which
groups' scores must be false.
For each case, the first line contains a positive integers M, which is the number of groups.
The i-th of the next M lines begins with a positive integer Bi representing the number of teams in the i-th group, followed by Bi nonnegative integers representing the score of each team in this group.
number of test cases <= 10
M<= 100
B[i]<= 20000
score of each team <= 20000
lines. Output ``F" (without quotes) if the scores in the i-th group
must be false, output ``T" (without quotes) otherwise. See samples for
detail.
3 0 5 1
2 1 1
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <climits>
#include <cstring>
#include <string>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <vector>
#include <list>
#define rep(i,m,n) for(i=m;i<=n;i++)
#define rsp(it,s) for(set<int>::iterator it=s.begin();it!=s.end();it++)
#define mod 1000000007
#define inf 0x3f3f3f3f
#define vi vector<int>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ll long long
#define pi acos(-1.0)
#define pii pair<int,int>
#define Lson L, mid, rt<<1
#define Rson mid+1, R, rt<<1|1
const int maxn=2e4+;
using namespace std;
ll gcd(ll p,ll q){return q==?p:gcd(q,p%q);}
ll qpow(ll p,ll q){ll f=;while(q){if(q&)f=f*p;p=p*p;q>>=;}return f;}
int n,m,k,t,a[maxn];
ll sum;
int main()
{
int i,j;
while(~scanf("%d",&t))
{
while(t--)
{
sum=;
scanf("%d",&n);
rep(i,,n)scanf("%d",&a[i]);
sort(a+,a+n+);
rep(i,,n)
{
sum+=a[i];
if(sum<(ll)i*(i-))break;
}
if(i<=n||sum!=(ll)n*(n-))puts("F");
else puts("T");
}
}
//system("Pause");
return ;
}
2016大连网络赛 Football Games的更多相关文章
- 2016大连网络赛 Different GCD Subarray Query
Different GCD Subarray Query Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65536/65536 K ( ...
- 2016大连网络赛 Function
Function Time Limit: 7000/3500 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Probl ...
- 2016大连网络赛 Sparse Graph
Sparse Graph Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) P ...
- 2016大连网络赛 Weak Pair
Weak Pair Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Prob ...
- HDU 5877 2016大连网络赛 Weak Pair(树状数组,线段树,动态开点,启发式合并,可持久化线段树)
Weak Pair Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Tota ...
- HDU 5869 Different GCD Subarray Query(2016大连网络赛 B 树状数组+技巧)
还是想不到,真的觉得难,思路太巧妙 题意:给你一串数和一些区间,对于每个区间求出区间内每段连续值的不同gcd个数(该区间任一点可做起点,此点及之后的点都可做终点) 首先我们可以知道每次添加一个值时gc ...
- 大连网络赛 1006 Football Games
//大连网络赛 1006 // 吐槽:数据比较水.下面代码可以AC // 但是正解好像是:排序后,前i项的和大于等于i*(i-1) #include <bits/stdc++.h> usi ...
- HDU 5880 Family View (2016 青岛网络赛 C题,AC自动机)
题目链接 2016 青岛网络赛 Problem C 题意 给出一些敏感词,和一篇文章.现在要屏蔽这篇文章中所有出现过的敏感词,屏蔽掉的用$'*'$表示. 建立$AC$自动机,查询的时候沿着$fa ...
- 16年大连网络赛 1006 Football Games
题目链接:http://acm.hdu.edu.cn/contests/contest_showproblem.php?cid=725&pid=1006 Football Games Time ...
随机推荐
- RecyclerView.Adapter
RecyclerView无需多说,是用于替代ListView的新控件.它的适配器在于灵活. 现在有一个需求:需要RecyclerView的item支持点击事件,并且下拉到最后时,显示ProgressB ...
- Flask -- 静态文件 和 模板渲染
静态文件 一般用于存放图片,样式文件(css, js等) 保存位置:包中或者文件所在目录创建一个 static 目录 访问:在应用中使用 /static/...即可访问 , 更好的方式是使用url_f ...
- 能加载文件或程序集“XXX”或它的某一个依赖项,系统找不到指定的文件
能加载文件或程序集“XXX”或它的某一个依赖项,系统找不到指定的文件 http://blog.csdn.net/pplcheer/article/details/7796211 做项目总是遇到各种的问 ...
- 1305: Substring
#include <iostream>#include<string.h>#include<stdio.h> using namespace std; #defin ...
- weka对数据进行预测
1.注意待预测数据集和训练用数据集各个属性的设置必须是一致的.即使你没有待预测数据集的Class属性的值,你也要添加这个属性,可以将该属性在各实例上的值均设成缺失值.比如你可以将欲预测的类别设为?即缺 ...
- Spring Security-用户密码自定义加密
public class SunPasswordEncoder implements PasswordEncoder{ //@实现加密的方法,既将明文转换为密文的方法 public String en ...
- VMware 全虚拟打开
1.修改.vmx 文件,最后一行加入: hypervisor.cpuid.v0 = “FALSE" mce.enable = “TRUE" vhv.enable = “TRUE&q ...
- laravel路由使用【总结】
1.路由参数 必选参数 有时我们需要在路由中捕获 URI 片段.比如,要从 URL 中捕获用户 ID,需要通过如下方式定义路由参数: Route::get('/test_param/{id}', 'T ...
- 打不开BT,一直重复的关闭开启。
/bt-btif (25335): ...preload_wait_timeout (retried:0/max-retry:1)...D/bt_userial(25335): RX terminat ...
- CSS中!important的使用 转
本篇文章使用最新的IE10以及firefox与chrome测试(截止2013年5月27日22::) CSS的原理: 我们知道,CSS写在不同的地方有不同的优先级, .css文件中的定义 < 元素 ...