2016大连网络赛 Football Games
Football Games
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
mysterious country will hold a football world championships---Abnormal
Cup, attracting football teams and fans from all around the world. This
country is so mysterious that none of the information of the games will
be open to the public till the end of all the matches. And finally only
the score of each team will be announced.
At the first phase of the championships, teams are divided into M
groups using the single round robin rule where one and only one game
will be played between each pair of teams within each group. The winner
of a game scores 2 points, the loser scores 0, when the game is tied
both score 1 point. The schedule of these games are unknown, only the
scores of each team in each group are available.
When those
games finished, some insider revealed that there were some false scores
in some groups. This has aroused great concern among the pubic, so the
the Association of Credit Management (ACM) asks you to judge which
groups' scores must be false.
For each case, the first line contains a positive integers M, which is the number of groups.
The i-th of the next M lines begins with a positive integer Bi representing the number of teams in the i-th group, followed by Bi nonnegative integers representing the score of each team in this group.
number of test cases <= 10
M<= 100
B[i]<= 20000
score of each team <= 20000
lines. Output ``F" (without quotes) if the scores in the i-th group
must be false, output ``T" (without quotes) otherwise. See samples for
detail.
3 0 5 1
2 1 1
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <climits>
#include <cstring>
#include <string>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <vector>
#include <list>
#define rep(i,m,n) for(i=m;i<=n;i++)
#define rsp(it,s) for(set<int>::iterator it=s.begin();it!=s.end();it++)
#define mod 1000000007
#define inf 0x3f3f3f3f
#define vi vector<int>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ll long long
#define pi acos(-1.0)
#define pii pair<int,int>
#define Lson L, mid, rt<<1
#define Rson mid+1, R, rt<<1|1
const int maxn=2e4+;
using namespace std;
ll gcd(ll p,ll q){return q==?p:gcd(q,p%q);}
ll qpow(ll p,ll q){ll f=;while(q){if(q&)f=f*p;p=p*p;q>>=;}return f;}
int n,m,k,t,a[maxn];
ll sum;
int main()
{
int i,j;
while(~scanf("%d",&t))
{
while(t--)
{
sum=;
scanf("%d",&n);
rep(i,,n)scanf("%d",&a[i]);
sort(a+,a+n+);
rep(i,,n)
{
sum+=a[i];
if(sum<(ll)i*(i-))break;
}
if(i<=n||sum!=(ll)n*(n-))puts("F");
else puts("T");
}
}
//system("Pause");
return ;
}
2016大连网络赛 Football Games的更多相关文章
- 2016大连网络赛 Different GCD Subarray Query
Different GCD Subarray Query Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65536/65536 K ( ...
- 2016大连网络赛 Function
Function Time Limit: 7000/3500 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Probl ...
- 2016大连网络赛 Sparse Graph
Sparse Graph Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) P ...
- 2016大连网络赛 Weak Pair
Weak Pair Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Prob ...
- HDU 5877 2016大连网络赛 Weak Pair(树状数组,线段树,动态开点,启发式合并,可持久化线段树)
Weak Pair Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Tota ...
- HDU 5869 Different GCD Subarray Query(2016大连网络赛 B 树状数组+技巧)
还是想不到,真的觉得难,思路太巧妙 题意:给你一串数和一些区间,对于每个区间求出区间内每段连续值的不同gcd个数(该区间任一点可做起点,此点及之后的点都可做终点) 首先我们可以知道每次添加一个值时gc ...
- 大连网络赛 1006 Football Games
//大连网络赛 1006 // 吐槽:数据比较水.下面代码可以AC // 但是正解好像是:排序后,前i项的和大于等于i*(i-1) #include <bits/stdc++.h> usi ...
- HDU 5880 Family View (2016 青岛网络赛 C题,AC自动机)
题目链接 2016 青岛网络赛 Problem C 题意 给出一些敏感词,和一篇文章.现在要屏蔽这篇文章中所有出现过的敏感词,屏蔽掉的用$'*'$表示. 建立$AC$自动机,查询的时候沿着$fa ...
- 16年大连网络赛 1006 Football Games
题目链接:http://acm.hdu.edu.cn/contests/contest_showproblem.php?cid=725&pid=1006 Football Games Time ...
随机推荐
- mysql 发生系统错误1067的解决方法
解决方法如下: 1.先删除mysql服务 控制面板->管理工具->服务,先停止mysql服务 开始->运行->输入cmd->sc delete mysql 服务删除 2. ...
- linux上安装配置samba服务器
linux上安装配置samba服务器 在linux上安装配置samba服务器 在这给大家介绍一个不错的家伙,samba服务.如果您正在犯愁,如何在Windows和Linux之间实现资源共享,就请看看这 ...
- hdu_5800_To My Girlfriend(变种背包)
题目链接:hdu_5800_To My Girlfriend 题意: 给你n和物品和一个重量m,让你求 题解: To My Girlfriend 令dp[i][j][s1][s2]表示前i个物品填了j ...
- div style设置隐藏多余字, title设置鼠标放上显示出来全部
<div style='overflow: hidden; white-space: nowrap; text-overflow: ellipsis;' title='"+data[j ...
- springmvc权限拦截器
配置文件spring-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <beans xm ...
- Entity Framework 学习中级篇2—存储过程(上)
目前,EF对存储过程的支持并不完善.存在以下问题: l EF不支持存储过程返回多表联合查询的结果集. l EF仅支持返回返回某个表的全部字段,以便转换成对应的实体.无法 ...
- MySQL主从配置【转载】
1.主从服务器分别作以下操作: 1.1.版本一致 1.2.初始化表,并在后台启动mysql 1.3.修改root的密码 2.修改主服务器master: #vi /etc/my.cnf ...
- 贪心+bfs 或者 并查集 Codeforces Round #268 (Div. 2) D
http://codeforces.com/contest/469/problem/D 题目大意: 给你一个长度为n数组,给你两个集合A.B,再给你两个数字a和b.A集合中的每一个数字x都也能在a集合 ...
- bfs UESTC 381 Knight and Rook
http://acm.uestc.edu.cn/#/problem/show/381 题目大意:给你两个棋子:车.马,再给你一个n*m的网格,从s出发到t,你可以选择车或者选择马开始走,图中有一些障碍 ...
- Qt多线程编程总结(一)
http://blog.csdn.net/mznewfacer/article/details/6965799 QMutex类 一个线程可以锁定互斥量,并且在它锁定之后,其它线程就不能再锁定这个互斥量 ...