hdu5007 小水题

题意：

      给你一个串，如果出现子串 “Apple”, “iPhone”, “iPod”, “iPad“输出MAI MAI MAI!，如果出现子串Sony 输出SONY DAFA IS GOOD!.

思路：

     水题，直接模拟就行了，题目是一组测试数据，说是输入的小于8KB，这个我没有算具体要开多大，为了省事，我直接没开数字，用%c直接累加模拟就行了，有个地方注意下'\n'不能忽略，也就是说Appl\ne ！= Apple.

#include<stdio.h>

int main ()
{
   int s1 ,s2 ,s3 ,s4 ,s5;
   char c;
   while(~scanf("%c" ,&c))
   {
      if(c == 'A') s1 = 1;
      else if(c == 'p' && s1 == 1) s1 = 2;
      else if(c == 'p' && s1 == 2) s1 = 3;
      else if(c == 'l' && s1 == 3) s1 = 4;
      else if(c == 'e' && s1 == 4)
      {
         printf("MAI MAI MAI!\n");
         continue;
      }else s1 = 0;

      if(c == 'i') s2 = 1;
      else if(c == 'P' && s2 == 1) s2 = 2;
      else if(c == 'h' && s2 == 2) s2 = 3;
      else if(c == 'o' && s2 == 3) s2 = 4;
      else if(c == 'n' && s2 == 4) s2 = 5;
      else if(c == 'e' && s2 == 5)
      {
         printf("MAI MAI MAI!\n");
         continue;
      }else s2 = 0;

      if(c == 'i') s3 = 1;
      else if(c == 'P' && s3 == 1) s3 = 2;
      else if(c == 'o' && s3 == 2) s3 = 3;
      else if(c == 'd' && s3 == 3)
      {
         printf("MAI MAI MAI!\n");
         continue;
      }else s3 = 0;

      if(c == 'i') s4 = 1;
      else if(c == 'P' && s4 == 1) s4 = 2;
      else if(c == 'a' && s4 == 2) s4 = 3;
      else if(c == 'd' && s4 == 3)
      {
         printf("MAI MAI MAI!\n");
         continue;
      }else s4 = 0;

      if(c == 'S') s5 = 1;
      else if(c == 'o' && s5 == 1) s5 = 2;
      else if(c == 'n' && s5 == 2) s5 = 3;
      else if(c == 'y' && s5 == 3)
      {
         printf("SONY DAFA IS GOOD!\n");
         continue;
      }else s5 = 0;

   }
   return 0;
}