YTU 2209: 建立链表(线性表)

2209: 建立链表(线性表)

时间限制: 1 Sec  内存限制: 128 MB

提交: 282  解决: 185

题目描述

（线性表）设键盘输入n个英语单词，输入格式为n, w1, w2, …,wn,其中n表示随后输入英语单词个数，试编一程序，建立一个单向链表，实现：如果单词重复出现，则只在链表上保留一个。

输入

4

now come now please

输出

now come please

样例输入

3
go come keep

样例输出

go come keep 

迷失在幽谷中的鸟儿，独自飞翔在这偌大的天地间，却不知自己该飞往何方……

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct Node
{
    char word[20];
    int times;
    Node* next;
};
Node* GetNode()
{
    Node* p = (Node*)malloc(sizeof(Node));
    p->next = 0;
    p->times = 1;
    memset(p->word, 0, 20);
    return p;
}
void DestroyList(Node* head)
{
    Node* p = head;
    while (p)
    {
        Node* q = p;
        p = p->next;
        free(q);
    }
}
Node* InsertNode(Node* head, char word[20])
{
    Node* p = head;
    while (p)
    {
        if ( strcmp(p->word, word)==0 )
        {
            ++p->times;
            return p;
        }
        p = p->next;
    }
    return p;
}
void DisplayList(Node* head)
{
    while(head)
    {
        printf("%s ", head->word);
        head = head->next;
    }
}
int main()
{
    int num = 0;
    scanf("%d", &num);
    Node* head = GetNode();
    Node* work = head;
    for (int i=0; i<num; i++)
    {
        char word[20] = {0};
        scanf("%s", word);
        if ( InsertNode(head, word)==NULL )
        {
            Node* p = GetNode();
            strcpy(p->word, word);
            work->next = p;
            work = work->next;
        }
    }
    DisplayList(head->next);
    DestroyList(head);
    return 0;
}