[Algorithm] 2. Trailing Zeros
Description
Write an algorithm which computes the number of trailing zeros in n factorial.
Example
11! = 39916800, so the out should be 2
Challenge
O(log N) time
Answer
/*
* @param n: A long integer
* @return: An integer, denote the number of trailing zeros in n!
*/
long long trailingZeros(long long n) {
// write your code here, try to do it without arithmetic operators.
if(n<){
return ;
}
else{
return n/ + trailingZeros(n/);
}
}
Tips
This solution is implemented by a recursive method, we can also use a loop method to solve this problem.
/*
* @param n: A long integer
* @return: An integer, denote the number of trailing zeros in n!
*/
long long trailingZeros(long long n) {
// write your code here, try to do it without arithmetic operators.
long long result = ;
while ( n > )
{
result += n/;
n /= ;
} return result;
}
[Algorithm] 2. Trailing Zeros的更多相关文章
- Trailing Zeros
Write an algorithm which computes the number of trailing zeros in n factorial. Have you met this que ...
- 2. Trailing Zeros【easy】
2. Trailing Zeros[easy] Write an algorithm which computes the number of trailing zeros in n factoria ...
- lintcode :Trailing Zeros 尾部的零
题目: 尾部的零 设计一个算法,计算出n阶乘中尾部零的个数 样例 11! = 39916800,因此应该返回 2 挑战 O(logN)的时间复杂度 解题: 常用方法: 也许你在编程之美中看到,通过求能 ...
- [LeetCode] Factorial Trailing Zeros
Well, to compute the number of trailing zeros, we need to first think clear about what will generate ...
- codewars--js--Number of trailing zeros of N!
问题描述: Write a program that will calculate the number of trailing zeros in a factorial of a given num ...
- [CareerCup] 17.3 Factorial Trailing Zeros 求阶乘末尾零的个数
LeetCode上的原题,讲解请参见我之前的博客Factorial Trailing Zeroes. 解法一: int trailing_zeros(int n) { ; while (n) { re ...
- [LintCode] Trailing Zeroes 末尾零的个数
Write an algorithm which computes the number of trailing zeros in n factorial. Have you met this que ...
- 2016.5.16——leetcode:Rotate Array,Factorial Trailing Zeroe
Rotate Array 本题目收获: 题目: Rotate an array of n elements to the right by k steps. For example, with n = ...
- CF#538(div 2) C. Trailing Loves (or L'oeufs?) 【经典数论 n!的素因子分解】
任意门:http://codeforces.com/contest/1114/problem/C C. Trailing Loves (or L'oeufs?) time limit per test ...
随机推荐
- UVa 1161 Objective: Berlin (最大流)
题意:给定一些航班,每个航班有人数,和起始终止时间,每次转机要花半小时,问限制时间内最多能有多少人从起始城市到终点城市. 析:差不多是裸板网络流的最大流问题,把每个航班都拆成两个点,这两个点之间连接一 ...
- bzoj 1179: [Apio2009]Atm【tarjan+spfa】
明明优化了spfa还是好慢-- 因为只能取一次值,所以先tarjan缩点,把一个scc的点权和加起来作为新点的点权,然后建立新图.在新图上跑spfa最长路,最后把酒吧点的dis取个max就是答案. # ...
- css设置页面全屏背景
.background { background: url(xxx.png); background-size: 100% 100%; height: 100%; position: fixed; w ...
- POJ3320 Jessica's Reading Problem
Bryce1010模板 #include <stdio.h> #include <string.h> #include <stdlib.h> #include &l ...
- Minimal Ratio Tree HDU - 2489
Minimal Ratio Tree HDU - 2489 暴力枚举点,然后跑最小生成树得到这些点时的最小边权之和. 由于枚举的时候本来就是按照字典序的,不需要额外判. 错误原因:要求输出的结尾不能有 ...
- Linux环境下使用yum安装zip和unzip
Linux环境下使用yum安装zip和unzip. yum install zip yum install unzip
- Android偏好设置(2)为应用定义一个偏好设置xml
1.Defining Preferences in XML Although you can instantiate new Preference objects at runtime, you sh ...
- Multitenant best Practice clone pdb seed and Clone a Pluggable Database – 12c Edition
1. 1.Tnsnames when connecting to either Container or Pluggable instance The tnsnames.ora should be c ...
- 在spring data jpa中使用自定义转换器之使用枚举转换
转载请注明http://www.cnblogs.com/majianming/p/8553217.html 在项目中,经常会出现这样的情况,一个实体的字段名是枚举类型的 我们在把它存放到数据库中是需要 ...
- android开发学习--网络请求框架RxJava+Retrofit
看了好多的博客,终于弄清楚了Rxjava和Retrofit,给大家推荐几个不错的文章: https://gank.io/post/56e80c2c677659311bed9841 这个文章是只用Ret ...