Problem Description
After Xiaoteng took a math class, he learned a lot of different shapes, but Xiaoteng's favorite triangle is because he likes stable shapes, just like his style.

After the Xiaoxun knew it, he wanted to give a triangle as a gift to Xiaoteng. He originally planned to do one, but he was too tired. So he decided to bring some wooden sticks to Xiaoteng and let Xiaoteng make a triangle himself.

One day, Xiaoxun brought n sticks to Xiaoteng. Xiaoteng wanted to try to use three of them to form a triangle, but the number is too much, Xiaoteng stunned, so he can only ask for your help.

 
Input
There are mutiple test cases.

Each case starts with a line containing a integer  n(1≤n≤5×106)  which represent the number of sticks and this is followed by n positive intergers(smaller than 231−1) separated by spaces.

 
Output
YES or NO for each case mean Xiaoteng can or can't use three of sticks to form a triangle.
 
Sample Input
4
1 2 3 4
 
Sample Output
YES
 
Source
 
很水的题,原来输入的数据是排好序的,怪不得加上排序就超时了,对于排好序的,只需要判断相邻两个的和是否大于第三个就可以了,想一想画面,很好理解。
代码:
#include <iostream>
#include <cstdlib>
#include <cstdio> using namespace std;
int n,a[];
int main() {
while(~scanf("%d",&n)) {
for(int i = ;i < && i < n;i ++) {
scanf("%d",&a[i]);
}
int flag = ;
for(int i = ;i < n;i ++) {
scanf("%d",&a[i]);
if(flag) continue;
if(a[i - ] > a[i] - a[i - ]) {
flag = ;
}
}
puts(flag ? "YES" : "NO");
}
}

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