题目链接:https://vjudge.net/contest/242578#problem/B

Dasha decided to bake a big and tasty layer cake. In order to do that she went shopping and bought n rectangular cake layers. The length and the width of the i-th cake layer were ai and bi respectively, while the height of each cake layer was equal to one.

From a cooking book Dasha learned that a cake must have a form of a rectangular parallelepiped constructed from cake layers of the same sizes.

Dasha decided to bake the biggest possible cake from the bought cake layers (possibly, using only some of them). It means that she wants the volume of the cake to be as big as possible. To reach this goal, Dasha can cut rectangular pieces out of the bought cake layers. She always cuts cake layers in such a way that cutting lines are parallel to the edges of that cake layer. Dasha isn't very good at geometry, so after cutting out a piece from the original cake layer, she throws away the remaining part of it. Also she can rotate a cake layer in the horizontal plane (swap its width and length).

Dasha wants her cake to be constructed as a stack of cake layers of the same sizes. Each layer of the resulting cake should be made out of only one cake layer (the original one or cut out from the original cake layer).

Help Dasha to calculate the maximum possible volume of the cake she can bake using given cake layers.

Input

The first line contains an integer n (1 ≤ n ≤ 4000) — the number of cake layers that Dasha can use.

Each of the following n lines contains two integer numbers ai and bi (1 ≤ ai, bi ≤ 106) — the length and the width of i-th cake layer respectively.

Output

The first line of the output should contain the maximum volume of cake that can be baked using given layers.

The second line of the output should contain the length and the width of the resulting cake. If there are many solutions with maximum possible volume, print any of them.

Examples

Input
5
5 12
1 1
4 6
6 4
4 6
Output
96
6 4
Input
2
100001 900000
900001 100000
Output
180000000000
900000 100000

Note

In the first example Dasha doesn't use the second cake layer. She cuts 4 × 6 rectangle from the first cake layer and she uses other cake layers as is.

In the second example Dasha cuts off slightly from the both cake layers.

题目大意:输入n,代表蛋糕有n层,接下来n行代表每层蛋糕的长度宽度,每层蛋糕的高度都是1 ,长宽可以交换位置,问你长宽取值为多少时,切得的蛋糕体积最大

个人思路:由题可知,长宽的取值一定在已有的长宽中得到,这题其实就是暴力,枚举每一个长和每一个宽,取最大的那个就是答案了

看代码

#include<iostream>
#include<cstdio>
#include<cstring>
#include<stdio.h>
#include<string.h>
#include<cmath>
#include<math.h>
#include<algorithm>
#include<set>
#include<queue>
#include<map>
typedef long long ll;
using namespace std;
const ll mod=1e9+;
const int maxn=4e3+;
const int maxk=+;
const int maxx=1e4+;
const ll maxe=+;
#define INF 0x3f3f3f3f3f3f
struct cake
{
int w,l;
}a[maxn];
bool cmp(const cake a,const cake b)
{
return a.w<b.w;
}
int main()
{
ll n,ans=,answ,ansl;
int c[maxn];
cin>>n;
for(int i=;i<n;i++)
{
cin>>a[i].w>>a[i].l;
if(a[i].w>a[i].l)
swap(a[i].w,a[i].l);
}
sort(a,a+n,cmp);
for(int i=;i<n;i++)
{
int sum=;
for(int j=;j<n;j++)
{
if(a[j].l>=a[i].l)
{
c[sum++]=a[j].w;
}
}
for(int j=;j<sum;j++)
{
ll res;
res=(ll)a[i].l*c[j]*(sum-j);
if(res>ans)
{
ans=res;
answ=c[j];
ansl=a[i].l;
}
}
}
cout<<ans<<endl;
cout<<answ<<" "<<ansl<<endl;
return ;
}

CodeForces - 589B的更多相关文章

  1. CodeForces - 589B(暴力)

    题目链接:http://codeforces.com/problemset/problem/589/B 题目大意:告诉你n 个矩形,知道矩形的长度和宽度(长和宽可以互换),每个矩形的长度可以剪掉一部分 ...

  2. CodeForces 589B Layer Cake (暴力)

    题意:给定 n 个矩形是a*b的,问你把每一块都分成一样的,然后全放一块,高度都是1,体积最大是多少. 析:这个题,当时并没有完全读懂题意,而且也不怎么会做,没想到就是一个暴力,先排序,先从大的开始选 ...

  3. CodeForces - 589B(暴力+排序)

    Dasha decided to bake a big and tasty layer cake. In order to do that she went shopping and bought n ...

  4. python爬虫学习(5) —— 扒一下codeforces题面

    上一次我们拿学校的URP做了个小小的demo.... 其实我们还可以把每个学生的证件照爬下来做成一个证件照校花校草评比 另外也可以写一个物理实验自动选课... 但是出于多种原因,,还是绕开这些敏感话题 ...

  5. 【Codeforces 738D】Sea Battle(贪心)

    http://codeforces.com/contest/738/problem/D Galya is playing one-dimensional Sea Battle on a 1 × n g ...

  6. 【Codeforces 738C】Road to Cinema

    http://codeforces.com/contest/738/problem/C Vasya is currently at a car rental service, and he wants ...

  7. 【Codeforces 738A】Interview with Oleg

    http://codeforces.com/contest/738/problem/A Polycarp has interviewed Oleg and has written the interv ...

  8. CodeForces - 662A Gambling Nim

    http://codeforces.com/problemset/problem/662/A 题目大意: 给定n(n <= 500000)张卡片,每张卡片的两个面都写有数字,每个面都有0.5的概 ...

  9. CodeForces - 274B Zero Tree

    http://codeforces.com/problemset/problem/274/B 题目大意: 给定你一颗树,每个点上有权值. 现在你每次取出这颗树的一颗子树(即点集和边集均是原图的子集的连 ...

随机推荐

  1. HDOJ1059(多重部分和问题)

    #include<cstdio> #include<cstring> using namespace std; +; ]; int dp[SIZE]; bool check() ...

  2. HDOJ1015(简单深搜)

    Safecracker Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total ...

  3. 优秀开源项目之三:高性能、高并发、高扩展性和可读性的网络服务器架构State Threads

    译文在后面. State Threads for Internet Applications Introduction State Threads is an application library ...

  4. js基础之变量类型

    1.NAN(Not a number) 不是一个数字 自身:console.log(NaN==NaN)和console.log(NaN===NaN)返回值都是false; 其他函数,isNaN()可用 ...

  5. [.net]手机APP与IIS服务器联调配置

    前端时间写过一段时间接口,在后期的时候,出现了一些无法通过查看日志来找出问题所在的bug.于是,将手机APP连接到IIS服务器上进行调试,下面是配置的具体步骤 1. 配置IIS  添加网站,将物理路径 ...

  6. centos6 搭建IPSEC

    http://www.maxwhale.com/how-to-install-l2tp-vpn-on-centos/ http://blog.earth-works.com/2013/02/22/ho ...

  7. mysql设置远程登录

    服务器上,我们刚安装好MySQL后,是没有办法直接远程的,它只支持本地登录.所以我们必须要对刚安装好的MySQL进行设置,允许远程登录. 1. 使用“mysql -uroot -p”命令可以连接到本地 ...

  8. JAVA基础知识总结1(概述)

    JAVA概述: 1991 年Sun公司的James Gosling等人开始开发名称为 Oak 的语言,希望用于控制嵌入在有线电视交换盒.PDA等的微处理器. 1994年将Oak语言更名为Java. J ...

  9. df查看分区使用情况

    Linux df命令用于显示目前在Linux系统上的文件系统的磁盘使用情况统计.语法 df [选项]... [FILE]...     -a, --all 包含所有的具有 0 Blocks 的文件系统 ...

  10. 在虚拟机中的Ubuntu搭建java开发环境

    前提: 安装好虚拟机 在虚拟机中装好了Ubuntu系统 以上两步请参见我的博客(python进阶) 1 安装JDK 1.1 到官网下载jdk压缩包并保存在本地 jdk1.8:点击前往 1.2 在Ubu ...