PTA 估值一亿的AI核心代码

题面

比赛时被模拟题打自闭了，本来以为是个比较麻烦的模拟，实际上只要会C++的regex不到40行就能把这个题过掉了(orz smz）

regex是用来处理正则表达式，里面有个函数regex_replace(string s, regex re, string new_string)可以将s中满足正则表达式re的所有位置替换成new_string。

代码：

#include <bits/stdc++.h>
#include <regex>
using namespace std;
int main() {
	int n;
	scanf("%d", &n);
	getchar();
	while(n--) {
	     string s;
		getline(cin, s);
		cout << s << endl;
		s = regex_replace(s, regex(R"(\s+)"), " ");
		if(s.front() == ' ') s.erase(s.begin());
		if(s.back() == ' ') s.pop_back();
		s = regex_replace(s, regex(R"( !)"), "!");
		s = regex_replace(s, regex(R"( ,)"), ",");
		s = regex_replace(s, regex(R"( \.)"), ".");
		s = regex_replace(s, regex(R"( \?)"), "?");
		s = regex_replace(s, regex(R"( ')"), "'");
		for (auto &c : s) {
			if(c != 'I') c = tolower(c);
		}
		s = regex_replace(s, regex(R"(\bcan you\b)"), "_I can");
		s = regex_replace(s, regex(R"(\bcould you\b)"), "_I could");
		s = regex_replace(s, regex(R"(\bI\b)"), "you");
		s = regex_replace(s, regex(R"(\bme\b)"), "you");
		s = regex_replace(s, regex(R"(\?)"), "!");
		s = regex_replace(s, regex(R"(\b_I\b)"), "I");
		cout << "AI: " << s << endl;
	}
}