C - Heavy Transportation
//改版dijkstra
#include <iostream>
#include <algorithm> #define Faster ios::sync_with_stdio(false),cin.tie(0)
#define Read freopen("in.txt","r",stdin),freopen("out.txt","w",stdout)
#define Close fclose(stdin),fclose(stdout)
const int maxn = +;
using namespace std; const int INF = 0xfffff; int mp[maxn][maxn];
bool v[maxn];
int n, m;
int dis[maxn]; void dij(int be){
int Min, p;
v[be] = false;
for(int i = ;i <= n;i++){
dis[i] = mp[i][be];
}
dis[be] = ; for(int i = ;i <= n;i++){
Min = ;
for(int j = ;j <= n;j++){
if(v[j] && Min < dis[j]){
p = j;
Min = dis[j];
}
}
if(Min == )
break;
v[p] = false;
for(int j = ;j <= n;j++){
dis[j] = max(dis[j], min(dis[p],mp[p][j]));
}
}
} int main(){
Faster;
int t;
int cnt = ;
cin >> t;
while(t--){
cnt++;
cin >> n >> m;
for(int i = ;i <= n;i++){
dis[i] = ;
v[i] = true;
for(int j = ;j <= n;j++){
mp[i][j] = ;
}
}
for(int i = ;i < m;i++){
int x, y, z;
cin >> x >> y >> z;
if(mp[x][y] < z){
mp[x][y] = mp[y][x] = z;
}
} dij();
cout << "Scenario #" << cnt << ":"<< endl;
cout << dis[n] << endl << endl;
}
return ;
}
C - Heavy Transportation的更多相关文章
- POJ 1797 Heavy Transportation(最大生成树/最短路变形)
传送门 Heavy Transportation Time Limit: 3000MS Memory Limit: 30000K Total Submissions: 31882 Accept ...
- Heavy Transportation(最短路 + dp)
Heavy Transportation Time Limit:3000MS Memory Limit:30000KB 64bit IO Format:%I64d & %I64 ...
- POJ 1797 Heavy Transportation (Dijkstra变形)
F - Heavy Transportation Time Limit:3000MS Memory Limit:30000KB 64bit IO Format:%I64d & ...
- poj 1797 Heavy Transportation(最短路径Dijkdtra)
Heavy Transportation Time Limit: 3000MS Memory Limit: 30000K Total Submissions: 26968 Accepted: ...
- POJ 1797 Heavy Transportation
题目链接:http://poj.org/problem?id=1797 Heavy Transportation Time Limit: 3000MS Memory Limit: 30000K T ...
- POJ 1797 Heavy Transportation (最短路)
Heavy Transportation Time Limit: 3000MS Memory Limit: 30000K Total Submissions: 22440 Accepted: ...
- POJ 1797 Heavy Transportation (dijkstra 最小边最大)
Heavy Transportation 题目链接: http://acm.hust.edu.cn/vjudge/contest/66569#problem/A Description Backgro ...
- POJ1797 Heavy Transportation 【Dijkstra】
Heavy Transportation Time Limit: 3000MS Memory Limit: 30000K Total Submissions: 21037 Accepted: ...
- #图# #最大生成树# #kruskal# ----- OpenJudge 799:Heavy Transportation
OpenJudge 799:Heavy Transportation 总时间限制: 3000ms 内存限制: 65536kB 描述BackgroundHugo Heavy is happy. Afte ...
- poj 1797 Heavy Transportation(最大生成树)
poj 1797 Heavy Transportation Description Background Hugo Heavy is happy. After the breakdown of the ...
随机推荐
- HTTP Status 405
分析原因: 1.doPost()和getPost()两个方法继承了父类,造成出错.
- MySQL常用语句汇总--持续更新(2017-08-10)
修改表的字段结构: 表:mission_picture,新增字段:content,字段类型:text ALTER TABLE mission_picture ADD content text:
- VB.Command()的参数
VB.Command()的参数的来源有三个地方 1配置文件2启动参数3框架
- 对于URL中文和特殊字符的处理方法
1.中文的处理方法 NSString* string1 = @"https://www.cloudsafe.com/文件夹"; NSString* string2 = [strin ...
- POJ 2309 BST(二叉搜索树)
BST Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 8657 Accepted: 5277 Description C ...
- UVA10518 How Many Calls? —— 矩阵快速幂
题目链接:https://vjudge.net/problem/UVA-10518 题解: 问:求斐波那契数f[n]的时候调用了多少次f[n] = f[n-1] + f[n-2],没有记忆化,一直递归 ...
- BestCoder6 1002 Goffi and Squary Partition(hdu 4982) 解题报告
题目链接:http://bestcoder.hdu.edu.cn/contests/contest_showproblem.php?pid=1002&cid=530 (格式有一点点问题,直接粘 ...
- 「LuoguP3796」 【模板】AC自动机(加强版)
题目描述 有N个由小写字母组成的模式串以及一个文本串T.每个模式串可能会在文本串中出现多次.你需要找出哪些模式串在文本串T中出现的次数最多. 输入输出格式 输入格式: 输入含多组数据. 每组数据的第一 ...
- [SDOI2012]任务安排
[题目链接] https://www.lydsy.com/JudgeOnline/problem.php?id=2726 [算法] 此题与POJ1180非常相似 但是 , 此题中的t值可能为负 , 这 ...
- 洛谷 P3803 多项式乘法(FFT) —— FFT
题目:https://www.luogu.org/problemnew/show/P3803 终于学了FFT了! 参考博客:https://www.cnblogs.com/zwfymqz/p/8244 ...