链接:

https://ac.nowcoder.com/acm/contest/924/G

题意:

Farmer John has returned to the County Fair so he can attend the special events (concerts, rodeos, cooking shows, etc.). He wants to attend as many of the N (1 <= N <= 10,000) special events as he possibly can.

He's rented a bicycle so he can speed from one event to the next in absolutely no time at all (0 time units to go from one event to the next!).

Given a list of the events that FJ might wish to attend, with their start times (1 <= T <= 100,000) and their durations (1 <= L <= 100,000), determine the maximum number of events that FJ can attend. FJ never leaves an event early.

思路:

将持续时间改变成结束时间,然后直接按照结束时间贪心即可。

代码:

#include <bits/stdc++.h>

using namespace std;

typedef long long LL;
const int MAXN = 1e5 + 10;
const int MOD = 1e9 + 7;
int n, m, k, t; struct Node
{
int l, r;
bool operator < (const Node & that) const
{
if (this->r != that.r)
return this->r < that.r;
return this->l > that.l;
}
}node[MAXN]; int main()
{
cin >> n;
for (int i = 1;i <= n;i++)
{
cin >> node[i].l >> node[i].r;
node[i].r += node[i].l;
}
sort(node+1, node+1+n);
int last = 0, res = 0;
for (int i = 1;i <= n;i++)
{
if (node[i].l >= last)
res++, last = node[i].r;
}
cout << res << endl; return 0;
}

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