Buffered Channels and Worker Pools
原文链接:https://golangbot.com/buffered-channels-worker-pools/
buffered channels
- 带有缓冲区的channel 只有在缓冲区满之后 channel才会阻塞
WaitGroup
- 如果有多个 goroutine在后台执行 那么需要在主线程中 多次等待 可以有一个简单的方法 就是 通过WaitGroup 可以控制 Goroutines 直到它们都执行完成
例子
import (
"fmt"
"sync"
"time"
)
func process(i int, wg *sync.WaitGroup) {
fmt.Println("started Goroutine ", i)
time.Sleep(2 * time.Second)
fmt.Printf("Goroutine %d ended\n", i)
wg.Done()
}
func main() {
no := 3
var wg sync.WaitGroup
for i := 0; i < no; i++ {
wg.Add(1)
go process(i, &wg)
}
wg.Wait()
fmt.Println("All go routines finished executing")
}
Worker Pool Implementation
先贴一下个人理解的 程序执行的流程图

import (
"fmt"
"math/rand"
"sync"
"time"
)
type Job struct {
id int
randomno int
}
type Result struct {
job Job
sumofdigits int
}
var jobs = make(chan Job, 10)
var results = make(chan Result, 10)
func digits(number int) int {
sum := 0
no := number
for no != 0 {
digit := no % 10
sum += digit
no /= 10
}
time.Sleep(5 * time.Second)
return sum
}
func worker(wg *sync.WaitGroup) {
for job := range jobs {
output := Result{job, digits(job.randomno)}
results <- output
}
wg.Done()
}
func createWorkerPool(noOfWorkers int) {
var wg sync.WaitGroup
for i := 0; i < noOfWorkers; i++ {
wg.Add(1)
go worker(&wg)
}
wg.Wait()
close(results)
}
func allocate(noOfJobs int) {
for i := 0; i < noOfJobs; i++ {
randomno := rand.Intn(999)
job := Job{i, randomno}
jobs <- job
}
close(jobs)
}
func result(done chan bool) {
for result := range results {
fmt.Printf("Job id %d, input random no %d , sum of digits %d\n", result.job.id, result.job.randomno, result.sumofdigits)
}
done <- true
}
func main() {
startTime := time.Now()
noOfJobs := 100
go allocate(noOfJobs)
done := make(chan bool)
go result(done)
noOfWorkers := 10
createWorkerPool(noOfWorkers)
<-done
endTime := time.Now()
diff := endTime.Sub(startTime)
fmt.Println("total time taken ", diff.Seconds(), "seconds")
}
Buffered Channels and Worker Pools的更多相关文章
- 【Go入门教程7】并发(goroutine,channels,Buffered Channels,Range和Close,Select,超时,runtime goroutine)
有人把Go比作21世纪的C语言,第一是因为Go语言设计简单,第二,21世纪最重要的就是并行程序设计,而Go从语言层面就支持了并行. goroutine goroutine是Go并行设计的核心.goro ...
- 【Go入门教程9】并发(goroutine,channels,Buffered Channels,Range和Close,Select,超时,runtime goroutine)
有人把Go比作21世纪的C语言,第一是因为Go语言设计简单,第二,21世纪最重要的就是并行程序设计,而Go从语言层面就支持了并行. goroutine goroutine是Go并行设计的核心.goro ...
- A Tour of Go Buffered Channels
Channels can be buffered. Provide the buffer length as the second argument to make to initialize a b ...
- GO系列教程
1.介绍与安装 2.Hello World 3.变量 4. 类型 5.常量 6.函数(Function) 7.包 8.if-else 语句 9.循环 10.switch语句 11.数组和切片 12.可 ...
- goroutine与channels
goroutine(协程) 大家都知道java中的线程Thread,golang没有提供Thread的功能,但是提供了更轻量级的goroutine(协程),协程比线程更轻,创办一个协程很简单,只需要g ...
- 【转】 Anatomy of Channels in Go - Concurrency in Go
原文:https://medium.com/rungo/anatomy-of-channels-in-go-concurrency-in-go-1ec336086adb --------------- ...
- golang中channels的本质详解,经典!
原文:https://www.goinggo.net/2014/02/the-nature-of-channels-in-go.html The Nature Of Channels In Go 这篇 ...
- Why should I avoid blocking the Event Loop and the Worker Pool?
Don't Block the Event Loop (or the Worker Pool) | Node.js https://nodejs.org/en/docs/guides/dont-blo ...
- Go by Example
Go by Example Go is an open source programming language designed for building simple, fast, and reli ...
随机推荐
- Codeforces Round #561 (Div. 2) B. All the Vowels Please
链接:https://codeforces.com/contest/1166/problem/B 题意: Tom loves vowels, and he likes long words with ...
- Codeforces Round #431 (Div. 2) A
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break? Given ...
- 自动生成sql
添加下面这个类 public static class GetAllAttribute<T> where T : class { public static string Names; p ...
- (笔记)快速入门PADS logic 到 layout
以前从未接触过画板,先是硬着头皮边学边操作<Layout2007中文教程之PADS_Logic>,刚好在中秋节前把这个教程从头到尾通学了一遍,随后感觉这个教程有了方方面面但没有工程的系统性 ...
- GreenDao的简单使用说明(五)多表n:m
在设计一些比较复杂的数据库结构的时候,我们会遇到表之间是n:m的关系,就是常说的多对多的关系,最常用的情况,就是用户权限这块,日常最常见的就是学生与老师的关系了,哪么我们来看一下GreenDao中如何 ...
- 小目标 | Power BI新人快速上手手册
· 适用人群:数据分析专业人士,在数据分析方向需求发展人士 · 应用场景:数据汇报.数据可视化展现.数据建模分析 · 掌握难度:★★★★☆ 本期讲师 『PowerPivot工坊』公众号提供Power ...
- wpf ListBox删除选择项(支持多项)
搞了个ListBox删除选择项,开始老是不能把选择项删除干净,剩下几个.后来调试一下原来是ListBox在删除一个选择项之后立即更新,选择项也有变化.结果我想了个这样的方法来删除呵呵. Departm ...
- codeforce Gym 100500E IBM Chill Zone (SG函数)
关于sg函数这篇blog讲得很详细http://blog.csdn.net/logic_nut/article/details/4711489. sg函数的价值在于把复杂的游戏拆分成简单的游戏,然后通 ...
- [numpy] 基础练习 (一)
Numpy常用总结 基础要打牢,恩. 基础 # 0 - 9 arr = np.arange(10) # 3*3 bool np.full((3,3),true,dtype = bool) np.one ...
- [大坑]Could not create cudnn handle: CUDNN_STATUS_INTERNAL_ERROR
报错tensorflow/stream_executor/cuda/cuda_dnn.cc:338] Could not create cudnn handle: CUDNN_STATUS_INTER ...