n个数里选出m个不重复的数

void change(int *p,int a,int b)
{
	int tmp = *(p + a);
	*(p + a)  = *(p + b);
	*(p + b) = tmp;

}
int main()
{
	int a[100];
	for (int i = 0 ;i < 101;++i)
	{
		a[i] = i + 100;
	}
	for (int i = 99;i >= 90;--i)
	{
		change(a,i,rand()%i);
		cout << a[i] <<endl;
	}
	return 0;

}