One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop.

Please, check the guess of Alex. You are given descriptions of n laptops. Determine whether two described above laptops exist.

Input

The first line contains an integer n (1 ≤ n ≤ 105) — the number of laptops.

Next n lines contain two integers each, ai and bi (1 ≤ ai, bi ≤ n), where ai is the price of the i-th laptop, and bi is the number that represents the quality of the i-th laptop (the larger the number is, the higher is the quality).

All ai are distinct. All bi are distinct.

Output

If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes).

Examples

Input
2
1 2
2 1
Output
Happy Alex
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
const int m=1e6+;
struct node
{
int x,y;
}a[m];
bool cmp(node a,node b)
{
return a.x < b.x;
}
int main()
{
int n;
while(cin>>n)
{
for(int i=;i<n;i++)
scanf("%d %d",&a[i].x,&a[i].y);
sort(a,a+n,cmp);
int flag=;
for(int i=;i<n;i++)
{
if(a[i].x>a[i-].x&&a[i].y<a[i-].y)
{
flag=;
cout<<"Happy Alex"<<endl;
break;
}
}
if(flag)
cout<<"Poor Alex"<<endl;
}
}

浙南联合训练赛 B-Laptops的更多相关文章

  1. 浙南联合训练赛 H - The number of positions

    Petr stands in line of n people, but he doesn't know exactly which position he occupies. He can say ...

  2. 浙南联合训练赛 D - Broken Clock

    You are given a broken clock. You know, that it is supposed to show time in 12- or 24-hours HH:MM fo ...

  3. 2014 多校联合训练赛6 Fighting the Landlords

    本场比赛的三个水题之一,题意是两个玩家每人都持有一手牌,问第一个玩家是否有一种出牌方法使得在第一回和对方无牌可出.直接模拟即可,注意一次出完的情况,一开始没主意,wa了一发. #include< ...

  4. 2013暑假江西联合训练赛 -- by jxust_acm 解题报告

    第6题是利用周期性求解, 第7题是 (总的序列长度-最长的满足要求的序列长度) 第8题是 设定起点,可以找到最早出现的不满足条件,然后后面都是不满足的,利用队列求解这个过程 大神给的简单,精炼的题解. ...

  5. hdu 5381 The sum of gcd 2015多校联合训练赛#8莫队算法

    The sum of gcd Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) T ...

  6. 2015多校联合训练赛 Training Contest 4 1008

    构造题: 比赛的时候只想到:前面一样的数,后面 是类似1,2,3,4,5,6....t这 既是:t+1,t+1...,1,2,3,...t t+1的数目 可能 很多, 题解时YY出一个N 然后对N   ...

  7. hdu 5358 First One 2015多校联合训练赛#6 枚举

    First One Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Tota ...

  8. hdu 5361 2015多校联合训练赛#6 最短路

    In Touch Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total ...

  9. HDU 5358(2015多校联合训练赛第六场1006) First One (区间合并+常数优化)

    pid=5358">HDU 5358 题意: 求∑​i=1​n​​∑​j=i​n​​(⌊log​2​​S(i,j)⌋+1)∗(i+j). 思路: S(i,j) < 10^10 & ...

随机推荐

  1. java迭代map

    java迭代map: import java.util.HashMap; import java.util.Iterator; import java.util.Map; import java.ut ...

  2. IntelliJ IDEA2017 + Tomcat 设置热部署

    1.点击idea中tomcat设置 2.点击deployment查看Deploy at the server startup 中tomcat每次所运行的包是 xxxx:war 还是其他,如果是xxxx ...

  3. PCIe 调试

    ISE 生成PCIe核之后, 在ipcore_dir目录下会产生以下文件目录 目录下包含内容如下: The doc folder contains the PCIe Endpoint Block da ...

  4. 51nod加农炮

    这道题维护一下前缀最大值然后二分答案就好了哇 233 #include<cstdio> #include<cstring> #include<algorithm> ...

  5. 【洛谷】P1648 看守 (数学)

    题目链接 直接暴力搞\(O(n^2)\)显然是布星滴. 试想,若是一维,最远距离就是最大值减最小值. 现在推广到二维,因为有绝对值的存在,所以有四种情况 \((x1+y1) - (x2+y2), (x ...

  6. [bzoj2251][2010Beijing Wc]外星联络——后缀数组+暴力求解

    Brief Description 找到 01 串中所有重复出现次数大于 1 的子串.并按字典序输出他们的出现次数. Algorithm Design 求出后缀数组之后,枚举每一个后缀,对于每个后缀从 ...

  7. 关于vscode的个人配置

      vs code官方下载地址 : https://code.visualstudio.com/Download   下载好的vs code相当是一款纯文本编辑器,接下来开始进行对其配置:   页面设 ...

  8. hdu 2141 Can you find it?(二分查找)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2141 题目大意:查找是否又满足条件的x值. 这里简单介绍一个小算法,二分查找. /* x^2+6*x- ...

  9. bootstrap-datetimepicker年视图中endDate设置之后比正常时间提前两个月

    问题 bootstrap-datetimepicker年视图中endDate设置结束时间为2016-08,(即8月之后的日期不能选)而在日历上显示时为2016-06,相差两个月,即6月之后的日期不能选 ...

  10. Windows XP SP1 Privilege Escalation

    MS05-018 MS05-018 Works for Windows 2K SP3/4 | Windows XP SP1/2 Download ms05-018.exe: https://githu ...