入口

ApplicationContext ctx = new ClassPathXmlApplicationContext("classpath:bean*.xml");

    /**
* Main entry point.
* @return {@code true} if the string matches against the pattern, or {@code false} otherwise.
*/
public boolean matchStrings(String str, Map<String, String> uriTemplateVariables) {
Matcher matcher = this.pattern.matcher(str);
if (matcher.matches()) {
if (uriTemplateVariables != null) {
// SPR-8455
Assert.isTrue(this.variableNames.size() == matcher.groupCount(),
"The number of capturing groups in the pattern segment " + this.pattern +
" does not match the number of URI template variables it defines, which can occur if " +
" capturing groups are used in a URI template regex. Use non-capturing groups instead.");
for (int i = 1; i <= matcher.groupCount(); i++) {
String name = this.variableNames.get(i - 1);
String value = matcher.group(i);
uriTemplateVariables.put(name, value);
}
}
return true;
}
else {
return false;
}
}
}

最后发现 java.util.regex.Pattern 调用matches() 方法

从而得知 支持正则表达式。

总结:

classpath:bean*.xml
冒号前半部分是为了获取 classpath 文件路径,然后file.lists() 递归循环获取所有 文件路径 ,逐一与冒号后面的 pattern 匹配。

冒号分析

/**
* A {@link ResourcePatternResolver} implementation that is able to resolve a
* specified resource location path into one or more matching Resources.
* The source path may be a simple path which has a one-to-one mapping to a
* target {@link org.springframework.core.io.Resource}, or alternatively
* may contain the special "{@code classpath*:}" prefix and/or
* internal Ant-style regular expressions (matched using Spring's
* {@link org.springframework.util.AntPathMatcher} utility).
* Both of the latter are effectively wildcards.
*
* <p><b>No Wildcards:</b>
*
* <p>In the simple case, if the specified location path does not start with the
* {@code "classpath*:}" prefix, and does not contain a PathMatcher pattern,
* this resolver will simply return a single resource via a
* {@code getResource()} call on the underlying {@code ResourceLoader}.
* Examples are real URLs such as "{@code file:C:/context.xml}", pseudo-URLs
* such as "{@code classpath:/context.xml}", and simple unprefixed paths
* such as "{@code /WEB-INF/context.xml}". The latter will resolve in a
* fashion specific to the underlying {@code ResourceLoader} (e.g.
* {@code ServletContextResource} for a {@code WebApplicationContext}).
*
* <p><b>Ant-style Patterns:</b>
*
* <p>When the path location contains an Ant-style pattern, e.g.:
* <pre class="code">
* /WEB-INF/*-context.xml
* com/mycompany/**/applicationContext.xml
* file:C:/some/path/*-context.xml
* classpath:com/mycompany/**/applicationContext.xml</pre>
* the resolver follows a more complex but defined procedure to try to resolve
* the wildcard. It produces a {@code Resource} for the path up to the last
* non-wildcard segment and obtains a {@code URL} from it. If this URL is
* not a "{@code jar:}" URL or container-specific variant (e.g.
* "{@code zip:}" in WebLogic, "{@code wsjar}" in WebSphere", etc.),
* then a {@code java.io.File} is obtained from it, and used to resolve the
* wildcard by walking the filesystem. In the case of a jar URL, the resolver
* either gets a {@code java.net.JarURLConnection} from it, or manually parses
* the jar URL, and then traverses the contents of the jar file, to resolve the
* wildcards.
*
* <p><b>Implications on portability:</b>
*
* <p>If the specified path is already a file URL (either explicitly, or
* implicitly because the base {@code ResourceLoader} is a filesystem one,
* then wildcarding is guaranteed to work in a completely portable fashion.
*
* <p>If the specified path is a classpath location, then the resolver must
* obtain the last non-wildcard path segment URL via a
* {@code Classloader.getResource()} call. Since this is just a
* node of the path (not the file at the end) it is actually undefined
* (in the ClassLoader Javadocs) exactly what sort of a URL is returned in
* this case. In practice, it is usually a {@code java.io.File} representing
* the directory, where the classpath resource resolves to a filesystem
* location, or a jar URL of some sort, where the classpath resource resolves
* to a jar location. Still, there is a portability concern on this operation.
*
* <p>If a jar URL is obtained for the last non-wildcard segment, the resolver
* must be able to get a {@code java.net.JarURLConnection} from it, or
* manually parse the jar URL, to be able to walk the contents of the jar,
* and resolve the wildcard. This will work in most environments, but will
* fail in others, and it is strongly recommended that the wildcard
* resolution of resources coming from jars be thoroughly tested in your
* specific environment before you rely on it.
*
* <p><b>{@code classpath*:} Prefix:</b>
*
* <p>There is special support for retrieving multiple class path resources with
* the same name, via the "{@code classpath*:}" prefix. For example,
* "{@code classpath*:META-INF/beans.xml}" will find all "beans.xml"
* files in the class path, be it in "classes" directories or in JAR files.
* This is particularly useful for autodetecting config files of the same name
* at the same location within each jar file. Internally, this happens via a
* {@code ClassLoader.getResources()} call, and is completely portable.
*
* <p>The "classpath*:" prefix can also be combined with a PathMatcher pattern in
* the rest of the location path, for example "classpath*:META-INF/*-beans.xml".
* In this case, the resolution strategy is fairly simple: a
* {@code ClassLoader.getResources()} call is used on the last non-wildcard
* path segment to get all the matching resources in the class loader hierarchy,
* and then off each resource the same PathMatcher resolution strategy described
* above is used for the wildcard subpath.
*
* <p><b>Other notes:</b>
*
* <p><b>WARNING:</b> Note that "{@code classpath*:}" when combined with
* Ant-style patterns will only work reliably with at least one root directory
* before the pattern starts, unless the actual target files reside in the file
* system. This means that a pattern like "{@code classpath*:*.xml}" will
* <i>not</i> retrieve files from the root of jar files but rather only from the
* root of expanded directories. This originates from a limitation in the JDK's
* {@code ClassLoader.getResources()} method which only returns file system
* locations for a passed-in empty String (indicating potential roots to search).
*
* <p><b>WARNING:</b> Ant-style patterns with "classpath:" resources are not
* guaranteed to find matching resources if the root package to search is available
* in multiple class path locations. This is because a resource such as
* <pre class="code">
* com/mycompany/package1/service-context.xml
* </pre>
* may be in only one location, but when a path such as
* <pre class="code">
* classpath:com/mycompany/**/service-context.xml
* </pre>
* is used to try to resolve it, the resolver will work off the (first) URL
* returned by {@code getResource("com/mycompany");}. If this base package
* node exists in multiple classloader locations, the actual end resource may
* not be underneath. Therefore, preferably, use "{@code classpath*:}" with the same
* Ant-style pattern in such a case, which will search <i>all</i> class path
* locations that contain the root package.
*
* @author Juergen Hoeller
* @author Colin Sampaleanu
* @author Marius Bogoevici
* @author Costin Leau
* @since 1.0.2
* @see #CLASSPATH_ALL_URL_PREFIX
* @see org.springframework.util.AntPathMatcher
* @see org.springframework.core.io.ResourceLoader#getResource(String)
* @see ClassLoader#getResources(String)
*/
public class PathMatchingResourcePatternResolver implements ResourcePatternResolver

PathMatchingResourcePatternResolver 的部分方法↓

   @Override
public Resource[] getResources(String locationPattern) throws IOException {
Assert.notNull(locationPattern, "Location pattern must not be null");
if (locationPattern.startsWith(CLASSPATH_ALL_URL_PREFIX)) {
// a class path resource (multiple resources for same name possible)
if (getPathMatcher().isPattern(locationPattern.substring(CLASSPATH_ALL_URL_PREFIX.length()))) {
// a class path resource pattern
return findPathMatchingResources(locationPattern);
}
else {
// all class path resources with the given name
return findAllClassPathResources(locationPattern.substring(CLASSPATH_ALL_URL_PREFIX.length()));
}
}
else {
// Only look for a pattern after a prefix here
// (to not get fooled by a pattern symbol in a strange prefix).
int prefixEnd = locationPattern.indexOf(":") + 1;
if (getPathMatcher().isPattern(locationPattern.substring(prefixEnd))) {
// a file pattern
return findPathMatchingResources(locationPattern);
}
else {
// a single resource with the given name
return new Resource[] {getResourceLoader().getResource(locationPattern)};
}
}
}

locationPattern 的两次值分别是:

  1. classpath:bean*.xml
  2. classpath:

第8行↑ 调用的方法参数是1,在该方法中再一次调用getResources,然后传的参数是2 (目的是为了获取rootDirResources)

第一个if else 是区分classpath*: 这是固定写法↓ ,然后回处理冒号左右↑

  /**
* Pseudo URL prefix for all matching resources from the class path: "classpath*:"
* This differs from ResourceLoader's classpath URL prefix in that it
* retrieves all matching resources for a given name (e.g. "/beans.xml"),
* for example in the root of all deployed JAR files.
* @see org.springframework.core.io.ResourceLoader#CLASSPATH_URL_PREFIX
*/
String CLASSPATH_ALL_URL_PREFIX = "classpath*:";

如果是classpath: 这是固定写法↓ ,则处理冒号左右

  /** Pseudo URL prefix for loading from the class path: "classpath:" */
String CLASSPATH_URL_PREFIX = ResourceUtils.CLASSPATH_URL_PREFIX;

如果是冒号右边是路径,则处理这个资源。↑

如果是冒号右边不是路径,则继续处理。↑【25行】——如下:

   @Override
public Resource getResource(String location) {
Assert.notNull(location, "Location must not be null");
if (location.startsWith("/")) {
return getResourceByPath(location);
}
else if (location.startsWith(CLASSPATH_URL_PREFIX)) {
return new ClassPathResource(location.substring(CLASSPATH_URL_PREFIX.length()), getClassLoader());
}
else {
try {
// Try to parse the location as a URL...
URL url = new URL(location);
return new UrlResource(url);
}
catch (MalformedURLException ex) {
// No URL -> resolve as resource path.
return getResourceByPath(location);
}
}
}

第7行,必须以classpath: 开始。↑

第8行,new ClassPathResource 的实例,其中第一个参数path为"" ,第二个参数为getClassLoader() 返回的实例。↑

   protected URL resolveURL() {
if (this.clazz != null) {
return this.clazz.getResource(this.path);
}
else if (this.classLoader != null) {
return this.classLoader.getResource(this.path);
}
else {
return ClassLoader.getSystemResource(this.path);
}
}

第6行 ,返回了类路径。↑   结果如下:↓

file:/E:/e/workspace/context/target/classes/

加载 bean*.xml的更多相关文章

  1. 加载 bean.xml 的几种方式 (java or web project)

    1. java project ApplicationContext ctx = new ClassPathXmlApplicationContext("classpath:bean1.xm ...

  2. Bean XML 配置(1)- 通过XML配置加载Bean

    系列教程 Spring 框架介绍 Spring 框架模块 Spring开发环境搭建(Eclipse) 创建一个简单的Spring应用 Spring 控制反转容器(Inversion of Contro ...

  3. Spring多种加载Bean方式简析

    1 定义bean的方式 常见的定义Bean的方式有: 通过xml的方式,例如: <bean id="dictionaryRelMap" class="java.ut ...

  4. 【死磕 Spring】----- IOC 之 加载 Bean

    原文出自:http://cmsblogs.com 先看一段熟悉的代码: ClassPathResource resource = new ClassPathResource("bean.xm ...

  5. sping加载bean都发生了些什么

    问题描述:使用@Autowired注入的类,没有实例化 //Controller @RequestMapping(value="/deepblue") @Controller pu ...

  6. Dubbo实践(六)Spring加载Bean流程

    根据上一小节对于spring扩展schema的介绍,大概可以猜到dubbo中相关的内容是如何实现的. 再来回顾Dubbo实践(一)中定义的dubbo-provider.xml: <?xml ve ...

  7. spring容器扩展功能之一:spring加载ApplicationContext.xml的四种方式

    容器加载Bean的常见两个类ApplicationContext和BeanFactory, 一.首先,看看spring中加载配置在xml中的Bean对象到容器 spring 中加载xml配置文件的方式 ...

  8. spring加载bean流程解析

    spring作为目前我们开发的基础框架,每天的开发工作基本和他形影不离,作为管理bean的最经典.优秀的框架,它的复杂程度往往令人望而却步.不过作为朝夕相处的框架,我们必须得明白一个问题就是sprin ...

  9. IoC 之加载 Bean:总结

    上文中我们将bean已经加载到了IOC容器中,接下来我们将把IOC加载Bean出来进行代码解析 备注:(有些解释是参考别个博客的相关解释 )一起探讨请加我QQ:1051980588 bean 的初始化 ...

随机推荐

  1. winodws同步时间命令

    首先,你应该判断你的两台域控制器,哪一台担任PDC角色(默认的域内权威的时间服务源). 判断方法很简单,单击“开始”,单击“运行”,键入dsa.msc,然后点确定.这时会打开“Active Direc ...

  2. Linux环境安装jdk10

    一. 下载jdk 下载方式一:直接在linux上下载 wget --no-check-certificate --no-cookies --header "Cookie: oraclelic ...

  3. 【linux】U盘安装启动出现press the enter key to begin the installation process 就不动弹了

    今天在物理机上安装centOS6.5  64bit 系统的时候,出现了U盘安装启动出现press the enter key to begin the installation process 就不动 ...

  4. mybatis 高级映射 简单例子

    1.建表 DROP TABLE IF EXISTS `user`; CREATE TABLE `user` ( `gender` ) NOT NULL, `name` ) NOT NULL, `id` ...

  5. Java separatorChar 如何在Java里面添加 \

    Java手册 separatorChar public static final char separatorChar 与系统有关的默认名称分隔符.此字段被初始化为包含系统属性 file.separa ...

  6. Java-Runoob-高级教程-实例-环境设置实例:4.Java 实例 – 如何查看当前 Java 运行的版本?

    ylbtech-Java-Runoob-高级教程-实例-环境设置实例:4.Java 实例 – 如何查看当前 Java 运行的版本? 1.返回顶部 1. Java 实例 - 如何查看当前 Java 运行 ...

  7. ES6系列_5之字符串模版

    1.字符串模板对比引入: (1).之前我们也可以使用JavaScript输出模版字符串,通常是下面这样的: var restult= "姓名: <b>"+person. ...

  8. OpenCL 直方图

    ▶ 计算直方图,由原子计数和规约计算两部分组成 ● 最简单的版本,代码 // kernel.cl #pragma OPENCL EXTENSION cl_khr_local_int32_base_at ...

  9. 102. Binary Tree Level Order Traversal + 103. Binary Tree Zigzag Level Order Traversal + 107. Binary Tree Level Order Traversal II + 637. Average of Levels in Binary Tree

    ▶ 有关将一棵二叉树转化为二位表的题目,一模一样的套路出了四道题 ▶ 第 102 题,简单的转化,[ 3, 9, 20, null, null, 15, 7 ] 转为 [ [ 15, 7 ] , [ ...

  10. bootstrap更新数据层

    mq推送数据,表格实时更新,发现销毁表格不太合适,整体表格闪动,于是选择更新数据层. 先初始化表格,然后在推送数据的时候先循环遍历数据 例如: initDevTable(data.operatingL ...