Description

Consider a town where all the streets are one-way and each street leads from one intersection to another. It is also known that starting from an intersection and walking through town's streets you can never reach the same intersection
i.e. the town's streets form no cycles.



With these assumptions your task is to write a program that finds the minimum number of paratroopers that can descend on the town and visit all the intersections of this town in such a way that more than one paratrooper visits no intersection. Each paratrooper
lands at an intersection and can visit other intersections following the town streets. There are no restrictions about the starting intersection for each paratrooper.

Input

Your program should read sets of data. The first line of the input file contains the number of the data sets. Each data set specifies the structure of a town and has the format:




no_of_intersections

no_of_streets

S1 E1

S2 E2

......

Sno_of_streets Eno_of_streets



The first line of each data set contains a positive integer no_of_intersections (greater than 0 and less or equal to 120), which is the number of intersections in the town. The second line contains a positive integer no_of_streets, which is the number of streets
in the town. The next no_of_streets lines, one for each street in the town, are randomly ordered and represent the town's streets. The line corresponding to street k (k <= no_of_streets) consists of two positive integers, separated by one blank: Sk (1 <= Sk
<= no_of_intersections) - the number of the intersection that is the start of the street, and Ek (1 <= Ek <= no_of_intersections) - the number of the intersection that is the end of the street. Intersections are represented by integers from 1 to no_of_intersections.




There are no blank lines between consecutive sets of data. Input data are correct.

Output

The result of the program is on standard output. For each input data set the program prints on a single line, starting from the beginning of the line, one integer: the minimum number of paratroopers required to visit all the intersections
in the town.

Sample Input

2
4
3
3 4
1 3
2 3
3
3
1 3
1 2
2 3

Sample Output

2
1

关于最小覆盖:http://blog.csdn.net/u014665013/article/details/49870029

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
using namespace std;
#define MAX 125
int n;
int map[MAX][MAX];
bool visited[MAX];
int match[MAX]; bool find(int i) ///查找当前的i是否可以匹配
{
int j;
for(j=1;j<=n;j++)
{
if(map[i][j]&&!visited[j])
{
visited[j]=1;
if(match[j]==-1||find(match[j]))
{
match[j]=i;
return 1;
}
}
}
return 0;
}
int main()
{
int k,x,y,ans;
int T;
scanf("%d",&T);
while(T--)
{
ans=0;
scanf("%d%d",&n,&k);
memset(map,0,sizeof(map));
memset(match,-1,sizeof(match)); for(int i=0;i<k;i++)//对有意思的进行初始化
{
scanf("%d%d",&x,&y);
map[x][y]=1;
}
for(int i=1;i<=n;i++)
{
memset(visited,0,sizeof(visited));//开始标记为全部没有访问
if(find(i))
ans++;
}
printf("%d\n",n-ans);
}
return 0;
}

Air Raid(最小路径覆盖)的更多相关文章

  1. 【网络流24题----03】Air Raid最小路径覆盖

    Air Raid Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Su ...

  2. (hdu step 6.3.3)Air Raid(最小路径覆盖:求用最少边把全部的顶点都覆盖)

    题目: Air Raid Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total ...

  3. HDU1151 Air Raid —— 最小路径覆盖

    题目链接:https://vjudge.net/problem/HDU-1151 Air Raid Time Limit: 2000/1000 MS (Java/Others)    Memory L ...

  4. POJ 1422 Air Raid (最小路径覆盖)

    题意 给定一个有向图,在这个图上的某些点上放伞兵,可以使伞兵可以走到图上所有的点.且每个点只被一个伞兵走一次.问至少放多少伞兵. 思路 裸的最小路径覆盖. °最小路径覆盖 [路径覆盖]在一个有向图G( ...

  5. (step6.3.4)hdu 1151(Air Raid——最小路径覆盖)

    题意:     一个镇里所有的路都是单向路且不会组成回路. 派一些伞兵去那个镇里,要到达所有的路口,有一些或者没有伞兵可以不去那些路口,只要其他人能完成这个任务.每个在一个路口着陆了的伞兵可以沿着街去 ...

  6. hdu 1151 Air Raid 最小路径覆盖

    题意:一个城镇有n个路口,m条路.每条路单向,且路无环.现在派遣伞兵去巡逻所有路口,伞兵只能沿着路走,且每个伞兵经过的路口不重合.求最少派遣的伞兵数量. 建图之后的就转化成邮箱无环图的最小路径覆盖问题 ...

  7. Air Raid(最小路径覆盖)

    Air Raid Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 7511   Accepted: 4471 Descript ...

  8. poj 1422 Air Raid 最少路径覆盖

    题目链接:http://poj.org/problem?id=1422 Consider a town where all the streets are one-way and each stree ...

  9. hdu 1151 Air Raid(二分图最小路径覆盖)

    http://acm.hdu.edu.cn/showproblem.php?pid=1151 Air Raid Time Limit: 1000MS   Memory Limit: 10000K To ...

  10. POJ1422 Air Raid 【DAG最小路径覆盖】

    Air Raid Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6763   Accepted: 4034 Descript ...

随机推荐

  1. python批量制作雷达图

    老板要画雷达图,但是数据好多组怎么办?不能一个一个点excel去画吧,那么可以利用python进行批量制作,得到样式如下: 首先制作一个演示的excel,评分为excel随机数生成: 1 =INT(( ...

  2. Lombok - 消除冗长的 java 代码

    前言:    逛开源社区的时候无意发现的,用了一段时间,觉得还可以,特此推荐一下.    lombok 提供了简单的注解的形式来帮助我们简化消除一些必须有但显得很臃肿的 java 代码.特别是相对于 ...

  3. 股票自用指标 boll 菜刀

    BI:=(H+L+O+C)/; BOL:EMA(BI,N); UPPER:BOLL+N1*STD(CLOSE,N); LOWER:BOLL-N1*STD(CLOSE,N); MA1:MA(CLOSE, ...

  4. LintCode "Number of Islands II"

    A typical Union-Find one. I'm using a kinda Union-Find solution here. Some boiler-plate code - yeah ...

  5. erlang和java通信

    连接在 https://guts.me/2014/07/27/erlang-communicates-with-java/ 代码在 https://github.com/mingshun/jinter ...

  6. VS合集/6.0/2005/2008/2010/2012/2013 绿色版精简版

    VS合集/6.0/2005/2008/2010/2012/2013 绿色版精简版 找到这里的都是老司机,别的不多说了 链接: http://pan.baidu.com/s/1i5IyYZb       ...

  7. BestCoder HDU 5750 Dertouzos

    Dertouzos 题意: 有中文,不说. 题解: 我看了别人的题解,还有个地方没懂, 为什么是 if(d%prime[i]==0) break; ? 代码: #include <bits/st ...

  8. mvc无法找到资源

    昨天装了vs2015,但是第二步没有完成.今天急急忙忙的用13打开一个mvc的项目,但是添加的控制器怎么都不能访问. 无法找到资源. 说明: HTTP 404.您正在查找的资源(或者它的一个依赖项)可 ...

  9. CSS控制鼠标形状

    巧合要用到鼠标样式效果,就顺便整理了下十五种CSS鼠标样式.CSS鼠标样式语法如下:任意标签中插入 style="cursor:*"例 子:<span style=" ...

  10. RPC介绍

    转载http://blog.csdn.net/mindfloating/article/details/39474123/ 近几年的项目中,服务化和微服务化渐渐成为中大型分布式系统架构的主流方式,而 ...