Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000). 
 

Output

For each test case, you should output the Nth leap year from year Y. 
 

Sample Input

3
2005 25
1855 12
2004 10000
 

Sample Output

2108
1904
43236

Hint

 We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
         

 #include<iostream>
#include<cstring>
#include<cstdio>
#include<algorithm>
using namespace std;
int main()
{
int N,n,m;
scanf("%d",&N);
while(N--)
{
scanf("%d%d",&n,&m);
if((n%==&&n%==)||(n%!=&&n%==))
{
m--;
}
else
{
while(n--)
{
if((n%==&&n%==)||(n%!=&&n%==))
break;
}
}
for(int i=n/+;i<=(n+*m)/;i++)
{
if(i%!=)
{
m++;
}
}
printf("%d\n",n+*m);
}
}

CDZSC_2015寒假新人(1)——基础 h的更多相关文章

  1. CDZSC_2015寒假新人(2)——数学 H

    H - H Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status ...

  2. CDZSC_2015寒假新人(1)——基础 e

    Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever ...

  3. CDZSC_2015寒假新人(1)——基础 i

    Description “Point, point, life of student!” This is a ballad(歌谣)well known in colleges, and you mus ...

  4. CDZSC_2015寒假新人(1)——基础 g

    Description Ignatius likes to write words in reverse way. Given a single line of text which is writt ...

  5. CDZSC_2015寒假新人(1)——基础 f

    Description An inch worm is at the bottom of a well n inches deep. It has enough energy to climb u i ...

  6. CDZSC_2015寒假新人(1)——基础 d

    Description These days, I am thinking about a question, how can I get a problem as easy as A+B? It i ...

  7. CDZSC_2015寒假新人(1)——基础 c

    Description FatMouse prepared M pounds of cat food, ready to trade with the cats guarding the wareho ...

  8. CDZSC_2015寒假新人(1)——基础 b

    Description The highest building in our city has only one elevator. A request list is made up with N ...

  9. CDZSC_2015寒假新人(1)——基础 a

    Description Contest time again! How excited it is to see balloons floating around. But to tell you a ...

随机推荐

  1. hdu4296 贪心

    E - 贪心 Crawling in process... Crawling failed Time Limit:2000MS     Memory Limit:32768KB     64bit I ...

  2. jquery 1.9 之后toggle不能用的问题

    今天用到toggle这个方法,发现不是自己想要的效果,之前有用过好多次,一直都没有问题. 网上查了原因,才知道是版本的问题,jquery1.9之后toggle取消了.那么如果想要继续用toggle的这 ...

  3. MSSQL-资源地址

    1.SQL-SERVER客户端管理工具.下载地址 https://msdn.microsoft.com/en-us/library/mt238290.aspx?f=255&MSPPError= ...

  4. [译]终极塔防——运用HTML5从头创建一个塔防游戏

    翻译共享一篇CodeProject的高星力作,原文地址:http://www.codeproject.com/Articles/737238/Ultimate-Tower-Defense 下载演示项目 ...

  5. Transposed Matrix

    Transposed Matrix In linear algebra, the transpose of a matrix A is another matrix AT (also written  ...

  6. 转:sql语句中GROUP BY 和 HAVING和使用 count()

    在开发时,我们经常会遇到以“累计(count)”或是“累加(sum)”为条件的查询.比如user_num表: id user num 1 a 3 2 a 4 3 b 5 4 b 7   例1:查询出现 ...

  7. POJ 1065 Wooden Sticks / hdu 1257 最少拦截系统 DP 贪心

    参考链接:http://blog.csdn.net/xiaohuan1991/article/details/6956629 (HDU 1257 解题思路一样就不继续讲解) POJ 1065题意:给你 ...

  8. python字符集选择

    # coding=utf8 或者 # -*- coding:utf-8 -*- 在python2 中默认是ASCII码的字符集,但可以引入其他的字符集  这个需要在头信息中引入: 而在python3中 ...

  9. xib和Storyboard 创建Cell的方式

    xib 方式 .在Cell.h文件中加一个宏 #define cellIdentifier @"customCell" . ViewController中: - (void)vie ...

  10. 基础总结篇之五:BroadcastReceiver应用详解

    問渠那得清如許?為有源頭活水來.南宋.朱熹<觀書有感> 据说程序员是最爱学习的群体,IT男都知道,这个行业日新月异,必须不断地学习新知识,不断地为自己注入新鲜的血液,才能使自己跟上技术的步 ...