TJU Problem 2548 Celebrity jeopardy
下次不要被长题目吓到,其实不一定难。
先看输入输出,再揣测题意。
原文:
2548. Celebrity jeopardy
Time Limit: 1.0 Seconds Memory Limit: 65536K
Total Runs: 1306 Accepted Runs: 898
will get it, yet still difficult enough to be worthy of some respect. Usually,
we err on one side or the other. How simple can a problem really be?
Here, as in Celebrity Jepoardy, questions and answers are a bit confused,
and, because the participants are celebrities, there's a real need to make the
challenges simple. Your program needs to prepare a question to be solved --- an
equation to be solved --- given the answer. Specifically, you have to write a
program which finds the simplest possible equation to be solved given the
answer, considering all possible equations using the standard mathematical
symbols in the usual manner. In this context, simplest can be defined
unambiguously several different ways leading to the same path of resolution. For
now, find the equation whose transformation into the desired answer requires the
least effort.
For example, given the answer X = 2, you might create the equation 9 - X = 7.
Alternately, you could build the system X > 0; X^2 = 4. These may not be the
simplest possible equations. Solving these mind-scratchers might be hard for a
celebrity.
Input
Each input line contains a solution in the form <symbol> =
<value>
Output
For each input line, print the simplest system of equations which would to
lead to the provided solution, respecting the use of space exactly as in the
input.
Sample Input
Y = 3
X=9
Sample Output
Y = 3
X=9
Source: Southeastern
European 2006
源代码:
#include <iostream>
#include <string>
using namespace std; int main() {
string aaa;
while (getline(cin, aaa)) {
cout << aaa << endl;
}
return ;
}
TJU Problem 2548 Celebrity jeopardy的更多相关文章
- Poj 3062 Celebrity jeopardy
1.Link: http://poj.org/problem?id=3062 2.Content: Celebrity jeopardy Time Limit: 1000MS Memory Lim ...
- Problem C: Celebrity Split
题目描写叙述 Problem C: Celebrity Split Jack and Jill have decided to separate and divide their property e ...
- Uva 01124, POJ 3062 Celebrity jeopardy
It's hard to construct a problem that's so easy that everyone will get it, yet still difficult enoug ...
- TJU Problem 2101 Bullseye
注意代码中: result1 << " to " << result2 << ", PLAYER 1 WINS."<& ...
- TJU Problem 2857 Digit Sorting
原题: 2857. Digit Sorting Time Limit: 1.0 Seconds Memory Limit: 65536KTotal Runs: 3234 Accepted ...
- TJU Problem 1015 Gridland
最重要的是找规律. 下面是引用 http://blog.sina.com.cn/s/blog_4dc813b20100snyv.html 的讲解: 做这题时,千万不要被那个图给吓着了,其实这题就是道简 ...
- TJU Problem 1065 Factorial
注意数据范围,十位数以上就可以考虑long long 了,断点调试也十分重要. 原题: 1065. Factorial Time Limit: 1.0 Seconds Memory Limit ...
- TJU Problem 1100 Pi
注: 1. 对于double计算,一定要小心,必要时把与double计算相关的所有都变成double型. 2. for (int i = 0; i < N; i++) //N 不 ...
- TJU Problem 2520 Quicksum
注意: for (int i = 1; i <= aaa.length(); i++) 其中是“ i <= ",注意等号. 原题: 2520. Quicksum Time L ...
随机推荐
- ReactiveCocoa入门教程--第二部分
翻译自:http://www.raywenderlich.com/62796/reactivecocoa-tutorial-pt2 ReactiveCocoa 是一个框架,它允许你在你的iOS程序中使 ...
- jvm加载类(更新中)
作为jvm的用户,从使用者角度来看,我们给jvm输入一个class文件,得到了一个Class对象.我们可以猜想下jvm加载类的过程:class文件有规定的格式,jvm去解析class文件流,读magi ...
- mac bash 下使用vi 快捷方式——因为没有alt键 所以没有办法 用vi模式也非常方便的
set -o emacs ##切到emacs模式 set -o vi ##切到vi模式 set -o ## 查看当前选项的设置状态 所以你只需要在.bashrc下加入 set -o vi 然后,使用E ...
- python字典和列表的高级应用
1.将序列分解为单独的变量 1.1问题 包含n个元素的元组或列表.字符串.文件.迭代器.生成器,将它分解为n个变量 1.2方案 直接通过赋值操作 要求:变量个数要等于元素个数 当执行分解操作时,有时需 ...
- WeRun is mini-app
WeRun is a mini-app within WeChat that allows users to monitor their daily step count. One of its mo ...
- Linux运维工程师真实的工作状态到底是怎么样的?
现在的运维工程师在大家眼中是个什么样子呢? 是不是还是把服务器搬来搬去,每天不是在拿着Linux光盘开始装系统,就是在等待系统安装完成.你如果还是这么想,那就大错特错了.现在又有做一个新的物种诞生,那 ...
- 通过改变unity中物体的alpha值实现若隐若现的效果
RawImage logo = mainLogo.transform.FindChild("back/headBack/Logo").GetComponent<RawImag ...
- Java 算法(背包,队列和栈)
Dijkstra的双栈算术表达式求值算法: import java.util.*; public class Main { public static double evaluate(String a ...
- BootstrapValidator验证
相关链接: https://www.cnblogs.com/wuwenshuai/p/7120755.html https://www.cnblogs.com/v-weiwang/p/4834672. ...
- Fedora的一些个人配置
0,老传统 yum install screenfetch 1,关闭蜂鸣器 edit /etc/bashrc setterm -blength 0#setterm -bfreq 10 #这个可以设置声 ...