组装数据--相同的clusterID合并在一起 左边是a接口 右边是B接口如 [{a接口},{b接口}]

组装成这种 

var BJData = [

[{"city": "无锡市","clusterID": 1, "y": 31.809979797058332}, { "city": "苏州市", "clusterID":1, "x": 120.7485913653},],

[{name:'北京'}, {name:'天津'}],

[{name:'北京'}, {name:'河南',type:"mt"}],

[{name:'北京'}, {name:'甘肃',type:"mt"}]

];

 data: {
              centerdata:[
                {"city": "无锡市","clusterID": 1,"y": 31.809979797058332},
                {"city": "廊坊市","clusterID": 2,"y": 39.215436433250005},
                {"city": "金华市","clusterID": 3,"y": 29.190387826775}
               ],

               sizhoudata:[
               { "city": "苏州市", "clusterID": 1, "x": 120.7485913653, },
               {"city": "重庆市","clusterID": 2,"x": 120.5818049003},
               {"city": "广汉市","clusterID": 3,"x": 140.5818049003}],
            },

　　

　　用了两个for循环，会循环3*3=9次

 created() {
              var newarr=[];
              for(let i in this.centerdata ){
                for(let j in this.sizhoudata){
                   if(this.centerdata[i].clusterID==this.sizhoudata[j].clusterID){
                      let arr=[this.centerdata[i],this.sizhoudata[j]]
                      newarr.push(arr);
                   }
                }
              }
              console.log(newarr)
            },