LeetCode 100. Same Tree (判断树是否完全相同)
100. Same Tree
Given two binary trees, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical and the nodes have the same value.
Example 1:
Input: 1 1
/ \ / \
2 3 2 3 [1,2,3], [1,2,3] Output: true
Example 2:
Input: 1 1
/ \
2 2 [1,2], [1,null,2] Output: false
Example 3:
Input: 1 1
/ \ / \
2 1 1 2 [1,2,1], [1,1,2] Output: false
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
if (p == NULL || q == NULL)
{
return (p == q);
} return (p->val == q->val) && isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
}
};
LeetCode 100. Same Tree (判断树是否完全相同)的更多相关文章
- [LeetCode]100. Same Tree判断树相同
dfs遍历一下判断 public boolean isSameTree(TreeNode p, TreeNode q) { if (p==null) { return q == null; } els ...
- [LeetCode] 100. Same Tree 相同树
Given two binary trees, write a function to check if they are the same or not. Two binary trees are ...
- LeetCode 100. Same Tree 判断两棵二叉树是否相等 C++
Given two binary trees, write a function to check if they are the same or not. Two binary trees are ...
- leetcode 100. Same Tree、101. Symmetric Tree
100. Same Tree class Solution { public: bool isSameTree(TreeNode* p, TreeNode* q) { if(p == NULL &am ...
- LeetCode OJ Symmetric Tree 判断是否为对称树(AC代码)
思路: 主要判断左子树与右子树. 在判断左时,循环下去肯定会到达叶子结点中最左边的结点与最右边的结点比较. 到了这一步因为他们都没有左(右)子树了,所以得开始判断这两个结点的右(左)子树了. 当某 ...
- LeetCode 100. Same Tree (相同的树)
Given two binary trees, write a function to check if they are equal or not. Two binary trees are con ...
- LeetCode 101. Symmetric Tree 判断对称树 C++
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For e ...
- [leetcode]100. Same Tree相同的树
Given two binary trees, write a function to check if they are the same or not. Two binary trees are ...
- LeetCode 100. Same Tree相同的树 (C++)
题目: Given two binary trees, write a function to check if they are the same or not. Two binary trees ...
随机推荐
- 【PyTorch v1.1.0文档研习】60分钟快速上手
阅读文档:使用 PyTorch 进行深度学习:60分钟快速入门. 本教程的目标是: 总体上理解 PyTorch 的张量库和神经网络 训练一个小的神经网络来进行图像分类 PyTorch 是个啥? 这是基 ...
- python3接口自动化:绕过验证码登陆
import requests import json from time import sleep class Test: url= "http://www.cnblogs.com/&qu ...
- 追光的人beta冲刺总结
所属课程 软件工程1916 作业要求 Beta冲刺博客汇总 团队名称 追光的人 作业目标 beta阶段总结 队员学号 队员博客 221600219 小墨 https://www.cnblogs.com ...
- 2019牛客暑期多校训练营(第八场)A:All-one Matrices(广告牌问题 单调队列)
题意:给出N*M的01矩阵,求矩阵个数,满足矩阵内全是‘1’,,而且被至少一个’0‘围住.(假设边界外是‘0’.(N,M<3000) 思路:这类问题,一般解决就是两个方向: A:压缩一维,即枚举 ...
- oracle中删除表:drop、delete、truncate
相同点,使用drop delete truncate 都会删除表中的内容 drop table 表名 delete from 表名(后面不跟where语句,则删除表中所有的数据) truncate t ...
- 虚拟机将ip修改为静态
- MongoDB权限配置
参考文章:https://blog.csdn.net/qq_26896281/article/details/81206492 https://blog.csdn.net/u012373281/art ...
- BZOJ 3048: [Usaco2013 Jan]Cow Lineup 双指针
看到这道题的第一个想法是二分+主席树(好暴力啊) 实际上不用这么麻烦,用一个双指针+桶扫一遍就行了 ~ code: #include <bits/stdc++.h> #define N 1 ...
- MYSQL索引的作用和创建
索引是查询优化最主要的方式: 查询方式: 一种是:全表扫描: 一种是:利用数据表上建立的所以进行扫描. 如:对表中name字段建立索引:则按照表中name字段进行索引排序,并为其建立指向数据表中记录所 ...
- luoguP4721 【模板】分治 FFT
P4721 [模板]分治 FFT 链接 luogu 题目描述 给定长度为 \(n-1\) 的数组 \(g[1],g[2],..,g[n-1]\),求 \(f[0],f[1],..,f[n-1]\),其 ...