Description

Given a nested list of integers, return the sum of all integers in the list weighted by their depth. Each element is either an integer, or a list -- whose elements may also be integers or other lists.

Example

Example 1:

Input: the list [[1,1],2,[1,1]],
Output: 10.
Explanation:
four 1's at depth 2, one 2 at depth 1, 4 * 1 * 2 + 1 * 2 * 1 = 10

Example 2:

Input: the list [1,[4,[6]]],
Output: 27.
Explanation:
one 1 at depth 1, one 4 at depth 2, and one 6 at depth 3; 1 + 4 * 2 + 6 * 3 = 27
思路:dfs 按照深度带权求和
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer,
* // rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds,
* // if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds,
* // if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class Solution {
public int depthSum(List<NestedInteger> nestedList) {
return helper(nestedList, 1);
} public int helper(List<NestedInteger> nestedList, int depth){
if (nestedList == null || nestedList.size() == 0)
return 0; int sum = 0;
for(NestedInteger ele : nestedList) {
if (ele.isInteger()) {
sum += ele.getInteger() * depth;
} else {
sum += helper(ele.getList(), depth + 1);
}
} return sum;
}
}

  

 

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