434. Number of Segments in a String

Easy

Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters.

Please note that the string does not contain any non-printable characters.

Example:

Input: "Hello, my name is John"
Output: 5
package leetcode.easy;

public class NumberOfSegmentsInAString {
public int countSegments1(String s) {
String trimmed = s.trim();
if (trimmed.equals("")) {
return 0;
}
return trimmed.split("\\s+").length;
} public int countSegments2(String s) {
int segmentCount = 0; for (int i = 0; i < s.length(); i++) {
if ((i == 0 || s.charAt(i - 1) == ' ') && s.charAt(i) != ' ') {
segmentCount++;
}
} return segmentCount;
} @org.junit.Test
public void test() {
System.out.println(countSegments1("Hello, my name is John"));
System.out.println(countSegments2("Hello, my name is John"));
}
}

LeetCode_434. Number of Segments in a String的更多相关文章

  1. [LeetCode] Number of Segments in a String 字符串中的分段数量

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  2. Leetcode: Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  3. 每天一道LeetCode--434. Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  4. 【LeetCode】434. Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  5. [Swift]LeetCode434. 字符串中的单词数 | Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  6. 434. Number of Segments in a String

    原题: 434. Number of Segments in a String 解题: 刚看到题目时,觉得可以通过统计空格个数,但想想有可能会有多个空格的情况 思路: 一:遍历字符,if条件碰到非空格 ...

  7. 434. Number of Segments in a String 字符串中的单词个数

    [抄题]: Count the number of segments in a string, where a segment is defined to be a contiguous sequen ...

  8. [LC] 434. Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  9. C#LeetCode刷题之#434-字符串中的单词数​​​​​​​(Number of Segments in a String)

    问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3941 访问. 统计字符串中的单词个数,这里的单词指的是连续的不是 ...

随机推荐

  1. c风格的字符串

    c风格的字符串的标注库 #include <cstring> 使用c 风格的字符串,牢记,其必须以null为结束标志 如 char ca[]={'c','+','='}; cout< ...

  2. 用java刷剑指offer(数组中只出现一次的数字)

    题目描述 一个整型数组里除了两个数字之外,其他的数字都出现了两次.请写程序找出这两个只出现一次的数字. 牛客网链接 思路 链接:https://www.nowcoder.com/questionTer ...

  3. Four subspaces - Prof. Strang

    相应地,用映射的观点考察映射σ的kernal space与image space,得到的就是下面这张图啦 Ref: Introduction to Linear Algebra 5th Edition ...

  4. 矩阵指数 Matrix Exponentials

    转自:https://zh.wikipedia.org/wiki/%E7%9F%A9%E9%98%B5%E6%8C%87%E6%95%B0 其中,X. X2.X3…….Xk 都是n阶矩阵,显然 exp ...

  5. Codeforces I. Barcelonian Distance(暴力)

    题目描述: In this problem we consider a very simplified model of Barcelona city. Barcelona can be repres ...

  6. Linux/Raspbian 每个目录用途说明

    本文转自无聊小博,很多刚接触树莓派/Linux 的同学会在给树莓派安装.卸载.配置软件时,软件和配置文件等存放在哪儿产生疑惑.也会遇到诸如“磁盘分区”.U盘挂载等涉及到的目录路径问题.Linux 的目 ...

  7. 最详细的keepalived+lvs-dr配置文档

    四台台机器: 分发器主:192.168.0.154 分发器备:192.168.0.171 rs_1:192.168.0.131 rs_2:192.168.0.132 keepalived安装: yum ...

  8. Spring中的applicationContext文件详解

    <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.sp ...

  9. tensorflow API _ 6 (tf.gfile)

    一.gfile模块是什么 tf.gfile模块的主要角色是:1.提供一个接近Python文件对象的API,以及2.提供基于TensorFlow C ++ FileSystem API的实现. C ++ ...

  10. tensorflow2.0 学习(二)

    线性回归问题 # encoding: utf-8 import numpy as np import matplotlib.pyplot as plt data = [] for i in range ...