Given a string containing only digits, restore it by returning all possible valid IP address combinations.

For example:
Given "25525511135",

return ["255.255.11.135", "255.255.111.35"]. (Order does not matter)

Solution:

注意这里if(tmp < 256 && tmp.toString().equals(s.substring(pos, pos + j)))

如果不加tmp.toString().equals(s.substring(pos, pos + j)), 则可能会出现001 这种情况, 即高位为0.

 public class Solution {
ArrayList<String> result = null;
public ArrayList<String> restoreIpAddresses(String s) {
// IMPORTANT: Please reset any member data you declared, as
// the same Solution instance will be reused for each test case.
result = new ArrayList<String>();
getAddress(s, 0, 4, new StringBuffer());
return result;
}
public void getAddress(String s, int pos, int num, StringBuffer sb){
if(num == 0 || pos == s.length()){
if(pos == s.length() && num == 0){
result.add(sb.substring(0, sb.length() - 1));
}
return;
}
for(int j = 1; j < 4 && pos + j <= s.length(); j ++){
Integer tmp = Integer.valueOf(s.substring(pos, pos + j));
if(tmp < 256 && tmp.toString().equals(s.substring(pos, pos + j))){
sb.append(s.substring(pos, pos + j));
sb.append(".");
getAddress(s, pos + j, num - 1, sb);
sb.delete(sb.length() - j - 1, sb.length());
}
}
}
}

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