Linked List Cycle II

Given a linked list, return the node where the cycle begins.
If there is no cycle, return null.

Note: Do not modify the linked list.

Follow up:
Can you solve it without using extra space?

 /*************************************************************************
> File Name: LeetCode142.c
> Author: Juntaran
> Mail: JuntaranMail@gmail.com
> Created Time: Mon 16 May 2016 19:46:12 PM CST
************************************************************************/ /************************************************************************* Linked List Cycle II Given a linked list, return the node where the cycle begins.
If there is no cycle, return null. Note: Do not modify the linked list. Follow up:
Can you solve it without using extra space? ************************************************************************/ #include <stdio.h> /**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* struct ListNode *next;
* };
*/
struct ListNode *detectCycle(struct ListNode *head)
{ struct ListNode *fast = head;
struct ListNode *slow = head; int count1 = ;
int count2 = ;
while( slow && fast && fast->next )
{
fast = fast->next->next;
slow = slow->next; if( slow == fast )
{
slow = head;
while( slow != fast )
{
slow = slow->next;
fast = fast->next;
}
return slow;
}
}
return NULL;
}

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