SQL Server 字符串拼接、读取

一、查询结果使用，字符串拼接

declare @names nvarchar(1000)
declare @ParmDefinition nvarchar(1000)
declare @sqltext nvarchar(500)
set @sqltext=N'Select @names=isnull(@names + '','' , '''' ) + isnull(列名, '''' ) From 表名'
set @ParmDefinition = N'@names nvarchar(1000) OUTPUT';
exec sp_executesql
  @sqltext,
  @ParmDefinition,
  @names=@names OUTPUT
select @names as Res

二、SQL函数 获取“，”字符串长度

Create function [dbo].[GetSplitLength]
(
  @String nvarchar(max), --要分割的字符串
  @Split nvarchar(10) --分隔符号
)
returns int
as
begin
  declare @location int
  declare @start int
  declare @length int

  set @String=ltrim(rtrim(@String))
  set @location=charindex(@split,@String)
  set @length=1
  while @location<>0
  begin
    set @start=@location+1
    set @location=charindex(@split,@String,@start)
    set @length=@length+1
  end
  return @length
end

三、SQL函数  遍历“，”拼接的字符串

create function [dbo].[GetSplitOfIndex]
 (
  @String nvarchar(max), --要分割的字符串
  @split nvarchar(10), --分隔符号
  @index int --取第几个元素
 )
 returns nvarchar(1024)
 as
 begin
  declare @location int
  declare @start int
  declare @next int
  declare @seed int

  set @String=ltrim(rtrim(@String))
  set @start=1
  set @next=1
  set @seed=len(@split)

  set @location=charindex(@split,@String)
  while @location<>0 and @index>@next
  begin
    set @start=@location+@seed
    set @location=charindex(@split,@String,@start)
    set @next=@next+1
  end
  if @location =0 select @location =len(@String)+1

  return substring(@String,@start,@location-@start)
 end

四、FOR XML PATH 使用　

SELECT 列名+',' FROM 表名 FOR XML PATH('')

https://www.cnblogs.com/doubleliang/archive/2011/07/06/2098775.html

五、IN 参数查询

create   function   [dbo].[f_split](@c   varchar(2000),@split   varchar(2))   

returns   @t   table(col   varchar(20))   

as   

    begin     

      while(charindex(@split,@c)<>0)   

        begin   

          insert   @t(col)   values   (substring(@c,1,charindex(@split,@c)-1))   

          set   @c   =   stuff(@c,1,charindex(@split,@c),'')   

        end   

      insert   @t(col)   values   (@c)   

      return   

    end

这样就可以直接使用IN来查询了 查询语句如下：

select schoolname  from school_info where code in(select col from [dbo].[f_split](@area,','))